Python 小练习一
1.如果同一个ip地址60s之内访问超过200次，那么就把ip加入黑名单
需求分析：
1.60s读一次文件
2.分割，取第一个元素，ip地址
3.把所有ip加入到一个list里面，如果ip次数超过200次加入黑名单
import time
point = 0 # 文件指针
while True:
blk_set = set() # 定义空集合，存放需要加入黑名单的ip
ips = [] # 存放所有ip地址
with open('access.log') as f:
f.seek(point)
for line in f:
ip = line.split()[0]
ips.append(ip)
if ips.count(ip) > 200:
blk_set.add(ip)
for ip in blk_set: # 去重
print('已把%s加入黑名单' % ip)
point = f.tell()
time.sleep(60)
2.判断是否为小数
# 小数点的个数，小数点的个数是否等于1
# 按照小数点分割
def check_float(s):
s = str(s)
if s.count('.') == 1:
s_list = s.split('.')
# 1.2 [1, 2]
# -5.3 [-5, 4]
left = s_list[0]
right = s_list[1]
if left.isdigit() and right.isdigit(): # 正小数
return True
elif left.startswith('-') and left.count('-') == 1: # 负小数
if left.split('-')[-1].isdigit() and right.isdigit():
return True
return False
3.对比字典内容
dict1 = {
"version": "9.0.0",
"is_test": True,
"store": "",
"urs": "",
"device": {
"os": "android",
"ime1": "99001062198893",
"device_id": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
"mac": "02:00:00:00:00:00",
"galaxy_tag": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
"udid": "a34b1f67dd5797df93fdd8b072f1fb8110fd0db6",
"network_status": "wifi"
},
"adunit": {
"category": "VIDEO",
"location": "1",
"app": "7A16FBB6",
"blacklist": ""
},
"ext_param": {
"is_start": 0,
"vId": "VW0BRMTEV"
}
}
dict2 = {
"version": "9.0.0",
"is_test": True,
"urs": "",
"store": "",
"device": {
"os": "android",
"imei": "99001062298893",
"device_id": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
"mac": "02:00:00:00:00:00",
"galaxy_tag": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",
"udid": "a34b1f67dd5797da93fdd8b072f1fb8110fd0db6",
"network_status": "wifi"
},
"adunit": {
"category": "VIDEO",
"location": "1",
"app": "7A16FBB6",
"blacklist": ""
}, "ext_param": {
"is_start": 0,
"vid": "VW0BRMTEV"
}
}
# 判断两个字典里面不一样的key，value
# 只需判断d1里面有
# 循环d1，通过key去d2里面取值
# 判断通过key取到的类型是什么，如果是字典的话，继续循环
# 然后再判断key和value
def compare(d1, d2):
for key in d1:
value1 = d1.get(key)
value2 = d2.get(key, '不存在')
if type(value1) == dict:
compare(value1, value2)
else:
if value1 != value2 and value2 == '不存在':
print('value不一样的key:%s，value1:%s，value2:%s' % (key, value1, value2))
res = set(d1.keys()).symmetric_difference(set(d2.keys())) # 对称差集，两个字典里面不一样的key
if res:
print('key不一样的是', ','.join(res))
compare(dict1, dict2)
