Python>>练习A1

# =====================================================================
# 自定义异常
# class FUSHUEXCEPTION(Exception):
#     def __init__(self,msg):
#         self.message = msg
# try:
#     a = int(input("被除数")) # ValueError
#     b = int(input("除数"))
#     if b < 0:
#         raise FUSHUEXCEPTION("不能为负")
#     c = a/b # ZeroDivisionError
#     print("%d/%d=%.2f"%(a,b,c))
# except FUSHUEXCEPTION as e:
#     print(e.message)
# =====================================================================
# PYTHON 异常处理
# try:
#     a = int(input("被除数")) # ValueError
#     b = int(input("除数"))
#     # + - * / // **
#     c = a/b # ZeroDivisionError
#     print("%d/%d=%.2f"%(a,b,c))
# except ZeroDivisionError:
#     print("除数不能为零")
# except ValueError:
#     print("输入必须是数字！")
# # except (ZeroDivisionError,ValueError): # 不能确定具体哪里错
# #     print("错误")
# else:
#     print("else0# 无异常，才执行")
# finally:
#     print("finally0# 无论是否异常，都执行")
# alist = [0,1,2]
# print(alist)
# =====================================================================
# =====================================================================
# '''
# 6、按照控制台提示输入1~3之间任一个数字，程序将输出相应的课程名称根据键盘输入进行判断。v
# (1）输入1:输出"Python语言设计"v(2）输入2:输出"Java语言程序设计"↓(3）输入3:输出“数据结构”v
# (4）如果输入其他数字，则输出该课程不存在
# (5）如果输入非数字字符，则抛出异常提示“输入错误”,(6）不管输入是否正确，均输出“欢迎提出建议!”
#
# '''
# try:
#     a = int(input("1-3\n"))
#     if a == 1:
#         print("Python语言设计")
#     elif a == 2:
#         print("Java语言程序设计")
#     elif a == 3:
#         print("数据结构")
#     else:
#         print("该课程不存在")
# except ValueError:
#     print("输入错误")
# finally:
#     print("欢迎提出建议!")
# =====================================================================
# '''
# 2、python中在定义函数时，若无法得知参数的个数，则可以定义可变长度的参数列表。v
# 按照要求编写函数:
# (1）定义一个函数mvavg，该方法使用可变长参数，计算任意众指定数字的平均值v
# (2）实现一个带默认参数的函数ceshi函数，可以计算m 的n次方，n设置默认值为5。v
# (3）测试上述函数
# '''
# def myavg(*a):
#     sum = 0
#     for x in a:
#         sum += x
#     return (sum/len(a))
# def ceshi(m,n=5):
#     return m**n
# if __name__ == "__main__":
#     print(myavg(1,2,3,4))
#     print(ceshi(2))
#     print(ceshi(2,3))
# else:
#     print(__name__)
# # =====================================================================
# 递归
# def fact(n):
#     if n==1:
#         return 1
#     return n*fact(n-1)
# print(fact(5))
# =====================================================================
# '''
# 4、按要求编写程序
# (1）封装自己的数学模块MyMath.py，要求如下:v①有一个PI变量，值为3.14159w
# ②有一个函数mvmax,完成求一组数据的最大值的功能
# (2)编写测试模块test.py,输出PI的值，调用函数mymax求一组数的最大值并输出。
# 运行效果如下: v
# PI的值为:3.14
# 7，22,3,9，12的最大值为:22
# 9'77,33的最大值为:77
# '''
# # test.py
# PI = 3.14159
# def mymax(*args):
#     return max(args)

# import myMath # 封装自己的数学模块MyMath.py
# print("PI的值为:{:.2f}".format(myMath.PI))
# print("7,22,3,9,12的最大值为:{}".format(myMath.mymax(7,22,3,9,12)))
# print("9,77,33的最大值为:{}".format(myMath.mymax(9,77,33)))
# =====================================================================
# '''
# 8、现有水果、雪梨、苹果、红苹果、青苹果等几个类，
# 水果有美容等功能。
# 雪梨除了美容的功能还有止咳的功能，
# 苹果除了美容的功能，还有被当成礼品赠送的功能。
# 红苹果的颜色是红的，青苹果的颜色是青的，
# 并且青苹果虽然有苹果的功能，但是青苹果一般丕用当礼品。
# 请根据上面的描述与自然界之间的具体关系，编写程序完成如下功能:u
# (1）通过 Python代码模拟出上面的事务与案例。,
# (2）通过Python代码判断青苹果的颜色，以及是否有美容的功能、是否有止咳的功能、是否有当礼品的功能。v
# '''
# class shuiguo0:
#     def meirong0(self):
#         print("美容")
# class xueli0(shuiguo0):
#     def zhike0(self):
#         print("止咳")
# class pingguo0(shuiguo0):
#     def __init__(self,color):
#         self.color = color
#     def gift(self):
#         print("送礼")
# class redapple0(pingguo0):
#     def __init__(self,color = "红色"):
#         super().__init__(color)
# class greenapple0(pingguo0):
#     def __init__(self,color = "青色"):
#         super().__init__(color)
#     def gift(self):
#         print("不送礼")
# g = greenapple0()
# print("{}苹果".format(g.color))
# g.meirong0()
# g.gift()
# =====================================================================

# =====================================================================
# * 号方框
# a0 = int(input(""))
# if a0 == 1:
#     print("*")
# elif a0 == 0:
#     print("")
# else:
#     for i in range(1,a0):
#         if i == 1:
#             print("* "*a0)
#         if i == a0-1:
#             print("* "*a0)
#         else:
#             print("* "+" "*(a0-2)*2+"*")
# =====================================================================

# =====================================================================
# '''
# 一、列表:
# 1.创建:alist=[110, "dog", "cat", 120, "apple"]
# 2.遍历(访问列表的每一个元素)
# 3.添加:append(元素)，extend（列表)， insert '
# 4.删除:del alist[下标]、pop(index)、remove(元素)
# 5.修改:直接给列表元素赋值
# 6.查找:index(元素,起始位置,结束为止)7.排序:列表.sort (key,reverse=False)  sorted(列表)
# '''
# =====================================================================
# li_num1 = [4,5,2,7]
# li_num2 = [3,6]
# li_num1.extend(li_num2)
# li_num1.sort(reverse=True)
# print(li_num1)
# =====================================================================
# tu_num1 = ('p','y','t',['o','n'])
# tu_num1[-1].append("h")
# print(tu_num1)
# =====================================================================
# '''
# 5、根据要求编写程序:v
# (1）创建列表[110, ...dog..., ...cat..,120, ...apple...]
# (2）在字符串...dog’..和’.cat’.之间插入空列表
# (3）删除列表中”..applem.这个字符串,
# (4）分别查找出列表中数值110、120(不能人工数，要采用列表提供的方法)+
# (5）对查找出来的数值110和120执行乘以10的操作运算
# (6）打印输出最终的列表
# '''
# alist = [110,'dog','cat',120,'apple']
# a0 = alist.index("cat")
# alist.insert(a0,[])
# alist.remove("apple")
#
# for i in range(len(alist)):
#     if alist[i] == 110:
#         print(alist[i])
#         alist[i] *= 10
#     if alist[i] == 120:
#         print(alist[i])
#         alist[i] *= 10
#
# # b0 = alist.index(110)
# # c0 = alist.index(120)
# # print(alist[b0])
# # print(alist[c0])
# # alist[b0] = alist[b0]*10
# # alist[c0] = alist[c0]*10
# print(alist)

# =====================================================================

# =====================================================================
# '''
# 3、输入一串字符串作为密码，密码只能由数字、字母与指定的特殊符号组成。编写程序判断输入的密码的强度，并输出，如下所示:
# 请输入测试密码（直接回车为退出):wabc123v
# abc123的密码强度为2级v'
# 请输入测试密码（直接回车为退出):Abc123v
# Abc123的密码强度为3级v'
# 判定标准如下，满足其中一条，密码强度增加一级:
# (1）有“，。! ? ;”特殊符号（2》有大写字母（3）有小写字母(4〉位数不小于8位(5)有数字v
# '''
# password = input("请输入一串字符串")
# len0 = 0
# s0 = 0
# dz0 = 0
# xz0 = 0
# zf0 = 0
# class yichang0(Exception):
#     def __init__(self,i):
#         self.message = i
# if len(password)==0:
#     print("退出")
# else:
#     try:
#         if len(password) >= 8:
#             len0 = 1
#         for i in password:
#             if 48 <= ord(i) <= 57:
#                 s0 = 1
#             elif 65 <= ord(i) <= 90:
#                 dz0 = 1
#             elif 97 <= ord(i) <= 122:
#                 xz0 = 1
#             # elif i == '"' or i == "," or i == "." or i == "!" or i == "?" or i == ";" or i == '"':
#             elif i == "“" or i == "，" or i == "。" or i == "！" or i == "？" or i == "；" or i == "”":
#                 zf0 = 1
#             else:
#                 raise yichang0(i)
#     except yichang0 as y0:
#         print(f"{y0.message}  不符合要求")
#     else:
#         if len0 == 1 :
#             print("长度符合")
#         if s0 == 1 :
#             print("数字符合")
#         if dz0 == 1 :
#             print("大写符合")
#         if xz0 == 1 :
#             print("小写符合")
#         if zf0 == 1 :
#             print("其他字符符合")
#         print("密码强度{}级".format(len0 + s0 + dz0 + xz0 + zf0))
# =====================================================================

# =====================================================================
# '''
# 字典
# '''
# # 1、创建字典
# adict =  {"中国":"北京","日本":"东京","韩国":"首尔"}
# bdict = dict(name = "jack",age  = 18,sex = "男")
# # 2、调用查找
# print(adict["中国"])
# # 3、添加修改
# adict["美国"] = "华盛顿"
# adict["韩国"] = "汉城"
# print(adict)
# # 4、删除
# # adict.pop("日本")
# # adict.popitem()
# # adict.clear()
# # print(adict)
# # 5、遍历
# print(adict.items())
# print(adict.keys())
# print(adict.values())
# =====================================================================
# str0 = "skdaskerkjsalkj"
# adict = {}
# for i in str0:
#     if i in adict:
#         adict[i] += 1
#     else:
#         adict[i] = 1
# print(str0)
# print(adict)

# =====================================================================