HDU 1036 字符串模拟题

这道字符串的题目其实并不简单，因为中间有许多的细节需要注意，注意这里的精度设计是四舍五入

/*
* Author:lonelycatcher
* problem:HDU 1036
* Type:字符串处理
*/
#include <iostream>
#include<string>
#include<string.h>
#include<stdio.h>
using namespace std;
int N,num;
double dis;
int main()
{
    setbuf(stdout,NULL);
    int i;
    cin>>N>>dis;
    while(cin>>num)
    {
        string s;
        int invalid=0;
        int hour=0,min=0,sec=0;
        for(i=0;i<N;i++)
        {
            cin>>s;
            if(s[0]=='-')
            {
                invalid=1;

            }
            if(invalid)continue;
            if(s.length()==8)
            {
                hour+=(s[0]-'0')*10+s[1]-'0';
                min+=((s[3]-'0')*10+s[4]-'0');
                sec+=((s[6]-'0')*10+s[7]-'0');
            }
            else
            {
                hour+=(s[0]-'0');
                min+=((s[2]-'0')*10+s[3]-'0');
                sec+=((s[5]-'0')*10+s[6]-'0');
            }

        }
        if(invalid)
        {
            printf("%3d: -\n",num);
            continue;
        }
        sec+=hour*3600+min*60;

        double second=(double)sec/dis;

        if(((int)(second*10))%10>=5)sec=(int)second+1;
        else sec=(int)second;
        min=sec/60;
        sec=sec%60;
        if(sec>=10)
        {
             printf("%3d: %d:%d min/km\n",num,min,sec);
             continue;
        }
        printf("%3d: %d:0%d min/km\n",num,min,sec);

    }
    return 0;
}