从URL获取参数

function getURLParam() {
  const url = location.search;
  const param: any = {};
  if (url.indexOf('?') != -1) {
      const str = url.substr(1);
      const strs = str.split('&');
      for(let i = 0; i < strs.length; i ++) {
        param[strs[i].split('=')[0]] = decodeURI(strs[i].split('=')[1]);
      }
  }
  return param;
}