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洛谷 P3384 【模板】树链剖分

洛谷 P3384 【模板】树链剖分

此博文只用来记录写树剖时我的错误(我写的真是太好看了!)

\(ps\):因为\(lfd\),我爱上了压行

\(1.\)不要混淆变量名、函数名,因为这个\(WA\)过(比如在\(dfs1\)里调用了\(dfs2\)……)
\(2.\)题目让你取模就不要忘记取模,第一次交只有部分取模了导致只有\(30\)分,而且要随时取模,随时取模, 随时取模!
\(3.\)全局变量初始值为\(0\),但局部变量并不是!!在线段树的\(asksum\)部分我没给\(ans\)赋初值,查错查了很久
\(4.\)跳的时候是跳到链顶的父亲节点那里!不是跳到链顶!
\(5.\)查询或修改树上两个点之间路径的时候是查询点之间的,所以一开始不需要用\(dfn[x]\),\(dfn[y]\),而查询或者修改一个子树的权值时,就要用到\(dfn[x]\)了,因为在第一遍\(dfs\)(我代码里的\(prepare\))之后,第二遍\(dfs\)就能够保证一棵子树的\(dfn\)序是连续的,所以可以直接用\(dfn[x]\)\(dfn[x] + siz[x] - 1\)来修改和查询这棵子树的权值和(因为自己也是自己子树的一员,所以要减一)

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;

const int A = 1e6 + 11;

inline int read() {
	char c = getchar(); int x = 0, f = 1;
	for( ; !isdigit(c); c = getchar()) if(c == '-') f = -1;
	for( ; isdigit(c); c = getchar()) x = (x << 3) + (x << 1) + (c ^ 48);
	return x * f;
}

int n, m, root, mod, w[A], pre[A];
struct node { int to, nxt; } e[A];
int head[A], cnt;

inline void add_edge(int from, int to) {	
	e[++cnt].to = to;
	e[cnt].nxt = head[from];
	head[from] = cnt;
}

namespace Seg {
	#define lson rt << 1
	#define rson rt << 1 | 1
	struct tree { int l, r, w, lazy; } t[A];
	inline void pushup(int rt) { t[rt].w = (t[lson].w + t[rson].w) % mod; }
	inline void pushdown(int rt) {
		t[lson].lazy = (t[lson].lazy + t[rt].lazy) % mod;
		t[rson].lazy = (t[rson].lazy + t[rt].lazy) % mod;
		t[lson].w += (t[lson].r - t[lson].l + 1) * t[rt].lazy; t[lson].w %= mod;
		t[rson].w += (t[rson].r - t[rson].l + 1) * t[rt].lazy; t[rson].w %= mod;
		t[rt].lazy = 0; return;
	}
	void build(int rt, int l, int r) {
		t[rt].l = l, t[rt].r = r;
		if(l == r) { t[rt].w = w[pre[l]] % mod; return; }
		int mid = (l + r) >> 1;
		build(lson, l, mid), build(rson, mid + 1, r);
		pushup(rt); return;
	}
	void update(int rt, int l, int r, int val) {
		if(l <= t[rt].l && t[rt].r <= r) {
			t[rt].lazy += val % mod; t[rt].lazy %= mod;
			t[rt].w += (t[rt].r - t[rt].l + 1) * val % mod; t[rt].w %= mod;
			return;
		}
		if(t[rt].lazy) pushdown(rt);
		int mid = (t[rt].l + t[rt].r) >> 1;
		if(l <= mid) update(lson, l, r, val);
		if(r > mid) update(rson, l, r, val);
		pushup(rt); return;
	} 
	int asksum(int rt, int l, int r) {
		if(l <= t[rt].l && t[rt].r <= r) { return t[rt].w % mod; }
		if(t[rt].lazy) pushdown(rt);
		int mid = (t[rt].l + t[rt].r) >> 1, ans = 0;
		if(l <= mid) ans += asksum(lson, l, r);
		if(r > mid) ans += asksum(rson, l, r);
		return ans;
	}
}

int dfn[A], top[A], siz[A], son[A], fa[A], tot, dep[A];

void prepare(int now, int fr) {
	siz[now] = 1, fa[now] = fr, dep[now] = dep[fr] + 1;
	for(int i = head[now]; i; i = e[i].nxt) {
		int to = e[i].to;
		if(to == fr) continue;
		prepare(to, now); siz[now] += siz[to];
		if(siz[to] > siz[son[now]]) son[now] = to;
	}
}

void dfs(int now, int tp) {
	dfn[now] = ++tot, pre[tot] = now, top[now] = tp;
	if(son[now]) dfs(son[now], tp);
	for(int i = head[now]; i; i = e[i].nxt) {
		int to = e[i].to;
		if(to == son[now] || to == fa[now]) continue;
		dfs(to, to);
	}
}

void update(int x, int y, int val) {
	while(top[x] != top[y]) {
		if(dfn[top[x]] < dfn[top[y]]) swap(x, y);
		Seg::update(1, dfn[top[x]], dfn[x], val);
		x = fa[top[x]];
	}
	if(dep[x] > dep[y]) swap(x, y);
	Seg::update(1, dfn[x], dfn[y], val);
	return;
}

int ask(int x, int y) {
	int ans = 0;
	while(top[x] != top[y]) {
		if(dfn[top[x]] < dfn[top[y]]) swap(x, y);
		ans += Seg::asksum(1, dfn[top[x]], dfn[x]), ans %= mod;
		x = fa[top[x]];
	}
	if(dep[x] > dep[y]) swap(x, y);
	ans += Seg::asksum(1, dfn[x], dfn[y]), ans %= mod;
	return (ans % mod + mod) % mod;
}

int main() {
	n = read(), m = read(), root = read(), mod = read();
	for(int i = 1; i <= n; i++) w[i] = read() % mod;
	for(int i = 1; i < n; i++) {
		int x = read(), y = read();
		add_edge(x, y), add_edge(y, x);
	}
	prepare(root, 0);
	dfs(root, root);
	Seg::build(1, 1, n);
	int opt, x, y, z;
	while(m--) {
		opt = read();
		if(opt == 1) x = read(), y = read(), z = read() % mod, update(x, y, z);
		if(opt == 2) x = read(), y = read(), cout << ask(x, y) % mod << '\n';
		if(opt == 3) x = read(), z = read(), Seg::update(1, dfn[x], dfn[x] + siz[x] - 1, z);
		if(opt == 4) x = read(), cout << Seg::asksum(1, dfn[x], dfn[x] + siz[x] - 1) % mod << '\n';
	}
}
posted @ 2019-11-06 10:34  Loceaner  阅读(120)  评论(2编辑  收藏  举报