爬虫:模拟登陆

注意:模拟登陆时,必须保证settings.py里的 COOKIES_ENABLED (Cookies中间件) 处于开启状态

COOKIES_ENABLED = True# COOKIES_ENABLED = False

策略一:直接POST数据(比如需要登陆的账户信息)

只要是需要提供post数据的,就可以用这种方法。下面示例里post的数据是账户密码:

# -*- coding: utf-8 -*-
import scrapy


class Renren1Spider(scrapy.Spider):
    name = "renren1"
    allowed_domains = ["renren.com"]

    def start_requests(self):
        url = 'http://www.renren.com/SysHome.do'
        # FormRequest 是Scrapy发送POST请求的方法
        yield scrapy.FormRequest(
                url = url,
                formdata = {"email" : "loaderman@163.com", "password" : "loaderman"},
                callback = self.parse_page)

    def parse_page(self, response):
        with open("mao2.html", "w") as filename:
            filename.write(response.body)

 

策略二:标准的模拟登陆步骤

模拟登录方法:

  1. 首先发送登录页面的get请求,获取到页面里的登录必须的参数(比如说zhihu登陆界面的 _xsrf)

  2. 然后和账户密码一起post到服务器,登录成功

# -*- coding: utf-8 -*-
import scrapy



class Renren2Spider(scrapy.Spider):
    name = "renren2"
    allowed_domains = ["renren.com"]
    start_urls = (
        "http://www.renren.com/PLogin.do",
    )

    # 处理start_urls里的登录url的响应内容,提取登陆需要的参数(如果需要的话)
    def parse(self, response):
        # 提取登陆需要的参数
        #_xsrf = response.xpath("//_xsrf").extract()[0]

        # 发送请求参数,并调用指定回调函数处理
        yield scrapy.FormRequest.from_response(
                response,
                formdata = {"email" : "loaderman@163.com", "password" : "loaderman"},#, "_xsrf" = _xsrf},
                callback = self.parse_page
            )

    # 获取登录成功状态,访问需要登录后才能访问的页面
    def parse_page(self, response):
        url = "http://www.renren.com/422167102/profile"
        yield scrapy.Request(url, callback = self.parse_newpage)

    # 处理响应内容
    def parse_newpage(self, response):
        with open("xiao.html", "w") as filename:
            filename.write(response.body)

 

策略三:直接使用保存登陆状态的Cookie模拟登陆

如果实在没办法了,可以用这种方法模拟登录,虽然麻烦一点,但是成功率100%

# -*- coding: utf-8 -*-
import scrapy

class RenrenSpider(scrapy.Spider):
    name = "renren"
    allowed_domains = ["renren.com"]
    start_urls = (
        'http://www.renren.com/111111',
        'http://www.renren.com/222222',
        'http://www.renren.com/333333',
    )

    cookies = {
    "anonymid" : "ixrna3fysufnwv",
    "_r01_" : "1",
    "ap" : "327550029",
    "JSESSIONID" : "abciwg61A_RvtaRS3GjOv",
    "depovince" : "GW",
    "springskin" : "set",
    "jebe_key" : "f6fb270b-d06d-42e6-8b53-e67c3156aa7e%7Cc13c37f53bca9e1e7132d4b58ce00fa3%7C1484060607478%7C1%7C1486198628950",
    "t" : "691808127750a83d33704a565d8340ae9",
    "societyguester" : "691808127750a83d33704a565d8340ae9",
    "id" : "327550029",
    "xnsid" : "f42b25cf",
    "loginfrom" : "syshome"
    }

    # 可以重写Spider类的start_requests方法,附带Cookie值,发送POST请求
    def start_requests(self):
        for url in self.start_urls:
            yield scrapy.FormRequest(url, cookies = self.cookies, callback = self.parse_page)

    # 处理响应内容
    def parse_page(self, response):
        print "===========" + response.url
        with open("deng.html", "w") as filename:
            filename.write(response.body)

 

posted on 2019-12-12 20:14  LoaderMan  阅读(237)  评论(0编辑  收藏  举报

导航