js小方法,获取知道公历生日 (‘1992-01-19’),获取阴历生日日期,属相,非简单根据年份判断-----------声明:整理自网络!!

 1 let lunar = {
 2   tg: '甲乙丙丁戊己庚辛壬癸',
 3   dz: '子丑寅卯辰巳午未申酉戌亥',
 4   number: '一二三四五六七八九十',
 5   year: '鼠牛虎兔龙蛇马羊猴鸡狗猪',
 6   month: '正二三四五六七八九十冬腊',
 7   monthadd: [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334],
 8   calendar: [0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95],
 9 };
10 // 获取阴历日期
11 const getLunarDate = (date) => {
12   let useDate = new Date();
13   let year,
14     month,
15     day;
16   if (!date) {
17     date = new Date(), year = date.getFullYear(), month = date.getMonth(), day = date.getDate();
18   } else {
19     date = date.split('-'), year = parseInt(date[0]), month = date[1] - 1, day = parseInt(date[2]);
20   }
21 
22   if (year < 1921 || year > 2020) {
23     return {};
24   }
25 
26   let total,
27     m,
28     n,
29     k,
30     bit,
31     lunarYear,
32     lunarMonth,
33     lunarDay;
34   let isEnd = false;
35   let tmp = year;
36   if (tmp < 1900) {
37     tmp += 1900;
38   }
39   total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + lunar.monthadd[month] + day - 38;
40   if (year % 4 == 0 && month > 1) {
41     total++;
42   }
43   for (m = 0; ; m++) {
44     k = (lunar.calendar[m] < 0xfff) ? 11 : 12;
45     for (n = k; n >= 0; n--) {
46       bit = (lunar.calendar[m] >> n) & 1;
47       if (total <= 29 + bit) {
48         isEnd = true;
49         break;
50       }
51       total = total - 29 - bit;
52     }
53     if (isEnd) break;
54   }
55   lunarYear = 1921 + m;
56   lunarMonth = k - n + 1;
57   lunarDay = total;
58   if (k == 12) {
59     if (lunarMonth == Math.floor(lunar.calendar[m] / 0x10000) + 1) {
60       lunarMonth = 1 - lunarMonth;
61     }
62     if (lunarMonth > Math.floor(lunar.calendar[m] / 0x10000) + 1) {
63       lunarMonth--;
64     }
65   }
66 
67   return {
68     lunarYear,
69     lunarMonth,
70     lunarDay,
71   };
72 };
73 
74 // 获取阴历年信息
75 const getLunarDateString = (lunarDate) => {
76   if (!lunarDate.lunarDay) return;
77   let data = {};
78   let lunarYear = lunarDate.lunarYear;
79   let lunarMonth = lunarDate.lunarMonth;
80   let lunarDay = lunarDate.lunarDay;
81 
82   data.tg = lunar.tg.charAt((lunarYear - 4) % 10);
83   data.dz = lunar.dz.charAt((lunarYear - 4) % 12);
84   data.year = lunar.year.charAt((lunarYear - 4) % 12);
85   data.month = lunarMonth < 1 ? `(闰)${lunar.month.charAt(-lunarMonth - 1)}` : lunar.month.charAt(lunarMonth - 1);
86 
87   data.day = (lunarDay < 11) ? '初' : ((lunarDay < 20) ? '十' : ((lunarDay < 30) ? '廿' : '三十'));
88   if (lunarDay % 10 != 0 || lunarDay == 10) {
89     data.day += lunar.number.charAt((lunarDay - 1) % 10);
90   }
91 
92   return data;
93 };
94 export default {
95   getLunarDate,
96   getLunarDateString,
97 };

用法:

import Zodiac from '../js/shengxiao.js';
Zodiac.getLunarDate('1992-1-19');   // 返回值 1991-12-15
Zodiac.getLunarDateString('1991-12-15');  // 返回值
{
day: "十五",
dz: "未",
month: "腊",
tg: "辛",
year: "羊"
 
posted @ 2019-01-22 09:31  秋风2016  阅读(606)  评论(0编辑  收藏  举报