python pygame 矩形的旋转

点旋转:

def count(angle,length):
# y = y2-y1
y = math.sin(math.pi * (angle / 180)) * length
y2 = int(y + y1)
# x = x2-x1
x = math.cos(math.pi * (angle / 180)) * length
x2 = int(x + x1)

return x2,y2

x2, y2 = count(angle, 50)
x3, y3 = count(angle1, 50)
x4, y4 = count(angle2, 71)
pygame.draw.line(screen, (1, 1, 1), (x1,y1),(x2,y2), 2)
pygame.draw.line(screen, (1, 1, 1), (x1,y1),(x3,y3), 2)
pygame.draw.line(screen, (1, 1, 1), (x3,y3),(x4,y4), 2)
pygame.draw.line(screen, (1, 1, 1), (x2,y2),(x4,y4), 2)


中心旋转
x0,y0 = 100,100
angle1 = 45
angle2 = 135
angle3 = 225
angle4 = 315
def count(angle,length):
# y = y2-y1
y = math.sin(math.pi * (angle / 180)) * length
y2 = int(y + y0)
# x = x2-x1
x = math.cos(math.pi * (angle / 180)) * length
x2 = int(x + x0)

return x2,y2
x1, y1 = count(angle1, 50)
x2, y2 = count(angle2, 50)
x3, y3 = count(angle3, 50)
x4, y4 = count(angle4, 50)
print(x1, y1,x2, y2,x3, y3,x4, y4)
pygame.draw.line(screen, (1, 1, 1), (x0,y0),(x1,y1), 2)
pygame.draw.line(screen, (1, 1, 1), (x0,y0),(x2,y2), 2)
pygame.draw.line(screen, (1, 1, 1), (x0,y0),(x3,y3), 2)
pygame.draw.line(screen, (1, 1, 1), (x0,y0),(x4,y4), 2)

pygame.draw.line(screen, (1, 1, 1), (x1,y1),(x2,y2), 2)
pygame.draw.line(screen, (1, 1, 1), (x2,y2),(x3,y3), 2)
pygame.draw.line(screen, (1, 1, 1), (x3,y3),(x4,y4), 2)
pygame.draw.line(screen, (1, 1, 1), (x4,y4),(x1,y1), 2)
posted @   记录——去繁就简  阅读(278)  评论(0编辑  收藏  举报
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