Codeforces 490E. Restoring Increasing Sequence 二分

统计有几个'?

',然后二分检測取满足条件的最小的数就能够了. 注意没有问号的时候也要检測一下....

E. Restoring Increasing Sequence

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Peter wrote on the board a strictly increasing sequence of positive integers a1, a2, ..., an. Then Vasil replaced some digits in the numbers of this sequence by question marks. Thus, each question mark corresponds to exactly one lost digit.

Restore the the original sequence knowing digits remaining on the board.

Input

The first line of the input contains integer n (1 ≤ n ≤ 105) — the length of the sequence. Next n lines contain one element of the sequence each. Each element consists only of digits and question marks. No element starts from digit 0. Each element has length from 1 to 8 characters, inclusive.

Output

If the answer exists, print in the first line "YES" (without the quotes). Next n lines must contain the sequence of positive integers — a possible variant of Peter's sequence. The found sequence must be strictly increasing, it must be transformed from the given one by replacing each question mark by a single digit. All numbers on the resulting sequence must be written without leading zeroes. If there are multiple solutions, print any of them.

If there is no answer, print a single line "NO" (without the quotes).

Sample test(s)

input

3
?
18
1?

output

YES
1
18
19

input

2
?
?
?

output

NO

input

5
12224
12??5
12226
?0000
?
00000

output

YES
12224
12225
12226
20000
100000

/* ***********************************************
Author        :CKboss
Created Time  :2015年03月14日 星期六 00时09分50秒
File Name     :CF490E_2.cpp
************************************************ */

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstdlib>
#include <vector>
#include <queue>
#include <set>
#include <map>

using namespace std;

char str[11];
int nine[10]={0,9,99,999,9999,99999,999999,9999999,99999999,999999999};
int len,ni;
vector<int> vi;
bool flag=true;
int fenjie[11],fn;

int getNUMBER(int mid)
{
	int tmid=mid;
	fn=0;
	if(mid==0) fenjie[fn++]=0;
	while(mid)
	{
		fenjie[fn++]=mid%10;
		mid/=10;
	}
	for(int i=fn;i<ni;i++) fenjie[fn++]=0;
	reverse(fenjie,fenjie+fn);
	int ret=0,nx=0;
	for(int i=0;i<len;i++)
	{
		int cs=0;
		if(str[i]!='?
') cs=str[i]-'0';
		else if(nx<fn) cs=fenjie[nx++];
		ret=ret*10+cs;
	}
	return ret;
}

int main()
{
    //freopen("in.txt","r",stdin);
    //freopen("out.txt","w",stdout);

	int T_T;
	vi.push_back(0);
	scanf("%d",&T_T);
	while(T_T--)
	{
		scanf("%s",str);
		len=strlen(str);

		if(flag==false) continue;
		/// find ?
		ni=0;
		for(int i=0;i<len;i++) if(str[i]=='?') ni++;
		bool FUCK = false;
		if(str[0]=='?') FUCK=true;
		if(ni==0)
		{
			int nb=0;
			for(int i=0;i<len;i++)
				nb=nb*10+(str[i]-'0');
			if(nb>*(--vi.end())) vi.push_back(nb);
			else flag=false;
		}
		else
		{
			int low=0,high=nine[ni],ans=-1;
			int lastnumber=*(--vi.end());
			if(FUCK) low=(int)(pow(10,ni-1));
			while(low<=high)
			{
				int mid=(low+high)/2;
				int num=getNUMBER(mid);
				if(num>lastnumber) { ans=num; high=mid-1; }
				else low=mid+1;
			}
			if(ans==-1) flag=false;
			else vi.push_back(ans);
		}
	}
	if(flag)
	{
		puts("YES");
		for(int i=1,sz=vi.size();i<sz;i++) printf("%d\n",vi[i]);
	}
	else puts("NO");
    
    return 0;
}