摘要: path 5000) useful.day 5000) index2012 <- array(dim=c(length(useful.day), 2)) for(i in useful.day){ index2012[which(i == useful.day), ] <- c(i, which(data[[i]][ , 5006] != "")[1]) } # 某些天不... 阅读全文
posted @ 2017-10-23 11:02 坴戋 阅读(200) 评论(0) 推荐(0) 编辑