django2.2和oracle11g版本冲突问题

上次用django2.2和oracle11g,在migrate的时候发生了版本冲突,最终 [ 将Oracle升级到了12c才解决问题

](https://www.jb51.net/article/189974.htm)

那么到底能不能用别的方法来解决这个冲突呢?想了个解决思路,实践一下:

用django2.2连Oracle12c环境下做migrate,创建基础表

将基础表导出,再导入到Oracle11g数据库中

用django2.2连Oracle11g

实施步骤

1、用django2.2连Oracle12c环境下做migrate,创建基础表

在前文中已经完成,连接到数据库,可以看到有10张基础表

看一张表,比如AUTH_GROUP表,发现有个ID字段是用了12c特有的generated语法,除了DJANGO_SESSION外,其他每张表都有一个自增序列的id字段作为主键。

    -- Create table
    create table AUTH_GROUP
    (
     id NUMBER(11) generated by default on null as identity,
     name NVARCHAR2(150)
    )
    tablespace DJANGO;
    -- Create/Recreate primary, unique and foreign key constraints 
    alter table AUTH_GROUP
     add primary key (ID)
     using index 
     tablespace DJANGO;
    alter table AUTH_GROUP
     add unique (NAME)
     using index 
     tablespace DJANGO;

2. 将基础表导出,再导入到Oracle11g数据库中

导出django用户数据库,注意使用11g版本

接着导入到11g数据库中,非常顺利

再看AUTH_GROUP表,发现表结构是一样的,但是id上面自增序列的默认值没有了。

    -- Create table
    create table AUTH_GROUP
    (
     id NUMBER(11) not null,
     name NVARCHAR2(150)
    )
    tablespace DJANGO;
    -- Create/Recreate primary, unique and foreign key constraints 
    alter table AUTH_GROUP
     add primary key (ID)
     using index 
     tablespace DJANGO;
    alter table AUTH_GROUP
     add unique (NAME)
     using index 
     tablespace DJANGO;

3、用django2.2连Oracle11g

修改settings文件,连Oracle11g,然后启动django服务,果然成功启动

但是,但是,创建admin用户密码的时候就报错了,ORA-01400: cannot insert NULL into
(“DJANGO”.“AUTH_USER”.“ID”)

    PS D:\parttime\python\django\guanxiangzhiji> python manage.py createsuperuser
    用户名 (leave blank to use 'administrator'):
    电子邮件地址:
    Password:
    Password (again):
    密码长度太短。密码必须包含至少 8 个字符。
    这个密码太常见了。
    Bypass password validation and create user anyway? [y/N]: y
    Traceback (most recent call last):
     File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
     return self.cursor.execute(sql, params)
     File "D:\app\anaconda\lib\site-packages\django\db\backends\oracle\base.py", line 510, in execute
     return self.cursor.execute(query, self._param_generator(params))
    cx_Oracle.IntegrityError: ORA-01400: cannot insert NULL into ("DJANGO"."AUTH_USER"."ID")
    
    The above exception was the direct cause of the following exception:
    
    Traceback (most recent call last):
     File "manage.py", line 21, in <module>
     main()
     File "manage.py", line 17, in main
     execute_from_command_line(sys.argv)
     File "D:\app\anaconda\lib\site-packages\django\core\management\__init__.py", line 381, in execute_from_command_line
     utility.execute()
     File "D:\app\anaconda\lib\site-packages\django\core\management\__init__.py", line 375, in execute
     self.fetch_command(subcommand).run_from_argv(self.argv)
     File "D:\app\anaconda\lib\site-packages\django\core\management\base.py", line 323, in run_from_argv
     self.execute(*args, **cmd_options)
     File "D:\app\anaconda\lib\site-packages\django\contrib\auth\management\commands\createsuperuser.py", line 61, in execute
     return super().execute(*args, **options)
     File "D:\app\anaconda\lib\site-packages\django\core\management\base.py", line 364, in execute
     output = self.handle(*args, **options)
     File "D:\app\anaconda\lib\site-packages\django\contrib\auth\management\commands\createsuperuser.py", line 156, in handle
     self.UserModel._default_manager.db_manager(database).create_superuser(**user_data)
     File "D:\app\anaconda\lib\site-packages\django\contrib\auth\models.py", line 162, in create_superuser
     return self._create_user(username, email, password, **extra_fields)
     File "D:\app\anaconda\lib\site-packages\django\contrib\auth\models.py", line 145, in _create_user
     user.save(using=self._db)
     File "D:\app\anaconda\lib\site-packages\django\contrib\auth\base_user.py", line 66, in save
     super().save(*args, **kwargs)
     File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 741, in save
     force_update=force_update, update_fields=update_fields)
     File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 779, in save_base
     force_update, using, update_fields,
     File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 870, in _save_table
     result = self._do_insert(cls._base_manager, using, fields, update_pk, raw)
     File "D:\app\anaconda\lib\site-packages\django\db\models\base.py", line 908, in _do_insert
     using=using, raw=raw)
     File "D:\app\anaconda\lib\site-packages\django\db\models\manager.py", line 82, in manager_method
     return getattr(self.get_queryset(), name)(*args, **kwargs)
     File "D:\app\anaconda\lib\site-packages\django\db\models\query.py", line 1186, in _insert
     return query.get_compiler(using=using).execute_sql(return_id)
     File "D:\app\anaconda\lib\site-packages\django\db\models\sql\compiler.py", line 1335, in execute_sql
     cursor.execute(sql, params)
     File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 99, in execute
     return super().execute(sql, params)
     File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 67, in execute
     return self._execute_with_wrappers(sql, params, many=False, executor=self._execute)
     File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 76, in _execute_with_wrappers
     return executor(sql, params, many, context)
     File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
     return self.cursor.execute(sql, params)
     File "D:\app\anaconda\lib\site-packages\django\db\utils.py", line 89, in __exit__
     raise dj_exc_value.with_traceback(traceback) from exc_value
     File "D:\app\anaconda\lib\site-packages\django\db\backends\utils.py", line 84, in _execute
     return self.cursor.execute(sql, params)
     File "D:\app\anaconda\lib\site-packages\django\db\backends\oracle\base.py", line 510, in execute
     return self.cursor.execute(query, self._param_generator(params))
    django.db.utils.IntegrityError: ORA-01400: cannot insert NULL into ("DJANGO"."AUTH_USER"."ID")
    

原因分析

很明显,插入到AUTH_USER表时,没有指定ID的值,而ID是主键,非空。

因为在12c的环境下,这个ID是自增序列,insert语句中不需要指定这个值。

解决方案

解决方案也应运而出了,只要为每个ID列创建一个11g的序列,创建触发器,在插入数据时补上id值就行了。

(1)生成序列。

用sql语句

    select 'create sequence seq_'||table_name||' minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;'
     from user_tab_columns
     where column_name='ID';

生成创建序列的批量执行语句,并执行。

    create sequence seq_DJANGO_ADMIN_LOG minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_AUTH_USER minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_AUTH_USER_GROUPS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_DJANGO_CONTENT_TYPE minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_AUTH_GROUP minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_AUTH_GROUP_PERMISSIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_DJANGO_MIGRATIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_AUTH_PERMISSION minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    create sequence seq_AUTH_USER_USER_PERMISSIONS minvalue 1 maxvalue 999999999 start with 1 increment by 1 cache 20;
    

(2)创建触发器

用SQL语句

    select 'create or replace trigger tri_'||table_name||'
     before insert
     on '||table_name||' 
     for each row
     declare
     begin
     :new.id:=seq_'||table_name||'.nextval;
     end tri_'||table_name||';
     /'
     from user_tab_columns
     where column_name='ID';
    

生成触发器脚本:

    create or replace trigger tri_DJANGO_MIGRATIONS
    	before insert
    	on DJANGO_MIGRATIONS
    	for each row
    declare
    begin
    	:new.id:=seq_DJANGO_MIGRATIONS.nextval;
    end tri_DJANGO_MIGRATIONS;
    /
    create or replace trigger tri_DJANGO_CONTENT_TYPE
    	before insert
    	on DJANGO_CONTENT_TYPE
    	for each row
    declare
    begin
    	:new.id:=seq_DJANGO_CONTENT_TYPE.nextval;
    end tri_DJANGO_CONTENT_TYPE;
    /
    create or replace trigger tri_AUTH_PERMISSION
    	before insert
    	on AUTH_PERMISSION
    	for each row
    declare
    begin
    	:new.id:=seq_AUTH_PERMISSION.nextval;
    end tri_AUTH_PERMISSION;
    /
    create or replace trigger tri_AUTH_GROUP
    	before insert
    	on AUTH_GROUP
    	for each row
    declare
    begin
    	:new.id:=seq_AUTH_GROUP.nextval;
    end tri_AUTH_GROUP;
    /
    create or replace trigger tri_AUTH_GROUP_PERMISSIONS
    	before insert
    	on AUTH_GROUP_PERMISSIONS
    	for each row
    declare
    begin
    	:new.id:=seq_AUTH_GROUP_PERMISSIONS.nextval;
    end tri_AUTH_GROUP_PERMISSIONS;
    /
    create or replace trigger tri_AUTH_USER
    	before insert
    	on AUTH_USER
    	for each row
    declare
    begin
    	:new.id:=seq_AUTH_USER.nextval;
    end tri_AUTH_USER;
    /
    create or replace trigger tri_AUTH_USER_GROUPS
    	before insert
    	on AUTH_USER_GROUPS
    	for each row
    declare
    begin
    	:new.id:=seq_AUTH_USER_GROUPS.nextval;
    end tri_AUTH_USER_GROUPS;
    /
    create or replace trigger tri_AUTH_USER_USER_PERMISSIONS
    	before insert
    	on AUTH_USER_USER_PERMISSIONS
    	for each row
    declare
    begin
    	:new.id:=seq_AUTH_USER_USER_PERMISSIONS.nextval;
    end tri_AUTH_USER_USER_PERMISSIONS;
    /
    create or replace trigger tri_DJANGO_ADMIN_LOG
    	before insert
    	on DJANGO_ADMIN_LOG
    	for each row
    declare
    begin
    	:new.id:=seq_DJANGO_ADMIN_LOG.nextval;
    end tri_DJANGO_ADMIN_LOG;
    /
    

(3)此时再创建admin用户,就成功了

新增用户lurenjia成功!

以上这篇基于django2.2连oracle11g解决版本冲突的问题就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持脚本之家。

在这里插入图片描述

posted @ 2021-06-15 21:16  老酱  阅读(176)  评论(0编辑  收藏  举报