摘要：
数值统计Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 67315 Accepted Submission(s): 3... 阅读全文
摘要：
平方和与立方和Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 109261 Accepted Submission(s): 3... 阅读全文
摘要：
求奇数的乘积Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 56573 Accepted Submission(s): 3649... 阅读全文
摘要：
第几天？Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 90652 Accepted Submission(s... 阅读全文
摘要：
第几天？Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 90652 Accepted Submissi... 阅读全文
摘要：
成绩转换Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 90024 Accepted Submission(s): 3... 阅读全文
摘要：
#include#includeint main(){double a;while(scanf("%lf",&a)!=EOF){ printf("%.2lf\n",fabs(a));}} 阅读全文
摘要：
#includemain(){int a,b,c,i;while(scanf("%d%d%d",&a,&b,&c)!=EOF){for(i=10;i<=100;i++)if(i%3==a&&i%5==b&&i%7==c) break;if(i<=100)printf("%d\n",i);else p... 阅读全文
摘要：
#include#include#define PI 3.1415927int main(){double a;while(scanf("%lf",&a)!=EOF){ printf("%.3lf\n",4*PI*pow(a,3)/3);}} 阅读全文
摘要：
#includemain(){float a,b;char c;printf("输入表达式如a+(* - /)b:\n");scanf("%f%c%f",&a,&c,&b);switch(c){case'+':printf("%f\n",a+b);break;case'-':printf("%f\n... 阅读全文