《程序员代码面试指南》第二章 链表问题 向有序环形单链表中插入新节点

样例

环形有序链表:1 2 4,插入 3,结果为:1 2 3 4

java代码

/**
 * @Description:向有序环形单链表中插入新节点
 * @Author: lizhouwei
 * @CreateDate: 2018/4/7 11:19
 * @Modify by:
 * @ModifyDate:
*/
public class Chapter2_18 {
    public Node insertNum(Node head, int value) {
        Node pre = head;
        Node cur = head.next;
        while (cur != head) {
            if (pre.vlaue < value && value < cur.vlaue) {
                break;
            }
            pre = cur;
            cur = cur.next;
        }
        Node node = new Node(value);
        pre.next = node;
        node.next = cur;
        return head.vlaue < value ? head : node;
    }

    public void print(Node head) {
        System.out.print(head.vlaue + " ");

        Node pre = head;
        Node cur = head.next;
        while (cur != head) {
            System.out.print(cur.vlaue + " ");
            cur = cur.next;
        }
    }

    //测试
    public static void main(String[] args) {
        Chapter2_18 chapter = new Chapter2_18();
        Link link = new Link();
        //构造链表
        for (int i = 10; i > 0; i--) {
            link.add(i);
        }
        Node node2 = new Node(2);
        Node node4 = new Node(4);
        Node node1 = new Node(1);
        node1.next = node2;
        node2.next = node4;
        node4.next = node1;
        chapter.print(node1);
        Node head = chapter.insertNum(node1, 3);
        chapter.print(head);
    }
}
posted @ 2018-04-07 11:34  lizhouwei  阅读(111)  评论(0编辑  收藏  举报