MySQL_Sql_打怪升级_进阶篇_进阶16: 视图
进阶16: 视图
16.1 视图介绍
含义:虚拟表,和普通表一样使用
MySQL从5.0.1版本开始提供视图功能。一种虚拟存在的表,行和列的数据来自定义视图的查询中使用的表
并且是在使用视图时动态生成的,只保存了sql逻辑,不保存查询结果。
应用场景:
多个地方用到同样的查询结果
该查询结果使用的sql语句较复杂
比如:舞蹈班和普通班级的对比
创建语法的关键字 是否实际占用物理空间 使用
视图 create view 只是保存了sql逻辑 增删改查,只是一般不能增删改
表 create table 保存了数据 增删改查
案例:查询姓张的学生名和专业名
#未使用视图,正常的查询
SELECT stuname,majorname
FROM stuinfo s
INNER JOIN major m ON s.`majorid`= m.`id`
WHERE s.`stuname` LIKE '张%';
#创建视图
CREATE VIEW v1
AS
SELECT stuname,majorname
FROM stuinfo s
INNER JOIN major m ON s.`majorid`= m.`id`;
#调用视图
SELECT * FROM v1 WHERE stuname LIKE '张%';
16.2 创建视图
语法:
create view 视图名
as
查询语句;
1.查询姓名中包含a字符的员工名、部门名和工种信息
USE myemployees;
①创建
CREATE VIEW myv1
AS
SELECT last_name,department_name,job_title
FROM employees e
JOIN departments d ON e.department_id = d.department_id
JOIN jobs j ON j.job_id = e.job_id;
②使用
SELECT * FROM myv1 WHERE last_name LIKE '%a%';
2.查询各部门的平均工资级别
#①创建视图查看每个部门的平均工资
CREATE VIEW myv2
AS
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id;
#②使用
SELECT myv2.`ag`,g.grade_level
FROM myv2
JOIN job_grades g
ON myv2.`ag` BETWEEN g.`lowest_sal` AND g.`highest_sal`;
3.查询平均工资最低的部门信息
SELECT * FROM myv2 ORDER BY ag LIMIT 1;
4.查询平均工资最低的部门名和工资
CREATE VIEW myv3
AS
SELECT * FROM myv2 ORDER BY ag LIMIT 1;
SELECT d.*,m.ag
FROM myv3 m
JOIN departments d
ON m.`department_id`=d.`department_id`;
16.3 修改视图
方式一:语法
create or replace view 视图名
as
查询语句;
示例
SELECT * FROM myv3
CREATE OR REPLACE VIEW myv3
AS
SELECT AVG(salary),job_id
FROM employees
GROUP BY job_id;
方式二:语法
alter view 视图名
as
查询语句;
示例
ALTER VIEW myv3
AS
SELECT * FROM employees;
16.4 删除视图
语法:drop view 视图名,视图名,...;
DROP VIEW emp_v1,emp_v2,myv3;
16.5 查看视图
DESC myv3;
SHOW CREATE VIEW myv3;
16.6 更新视图
CREATE OR REPLACE VIEW myv1
AS
SELECT last_name,email,salary*12*(1+IFNULL(commission_pct,0)) "annual salary"
FROM employees;
CREATE OR REPLACE VIEW myv1
AS
SELECT last_name,email
FROM employees;
SELECT * FROM myv1;
SELECT * FROM employees;
1.插入
INSERT INTO myv1 VALUES('张飞','zf@qq.com');
2.修改
UPDATE myv1 SET last_name = '张无忌' WHERE last_name='张飞';
3.删除
DELETE FROM myv1 WHERE last_name = '张无忌';
具备以下特点的视图不允许更新
分组函数、distinct、group by、having、union或者union all
常用视图:
1. select 中包含子查询
2. join
3. from 一个不能更新的视图
4. where子句的子查询引用了from子句中的表
#报错提示: is not updatable
①包含以下关键字的sql语句:分组函数、distinct、group by、having、union或者union all
CREATE OR REPLACE VIEW myv1
AS
SELECT MAX(salary) m,department_id
FROM employees
GROUP BY department_id;
SELECT * FROM myv1;
更新
UPDATE myv1 SET m=9000 WHERE department_id=10;
②常量视图
CREATE OR REPLACE VIEW myv2
AS
SELECT 'john' NAME;
SELECT * FROM myv2;
更新
UPDATE myv2 SET NAME='lucy';
③Select中包含子查询
CREATE OR REPLACE VIEW myv3
AS
SELECT department_id,(SELECT MAX(salary) FROM employees) 最高工资
FROM departments;
更新
SELECT * FROM myv3;
UPDATE myv3 SET 最高工资=100000;
④join
CREATE OR REPLACE VIEW myv4
AS
SELECT last_name,department_name
FROM employees e
JOIN departments d
ON e.department_id = d.department_id;
更新
SELECT * FROM myv4;
UPDATE myv4 SET last_name = '张飞' WHERE last_name='Whalen';
INSERT INTO myv4 VALUES('陈真','xxxx');
⑤from一个不能更新的视图
CREATE OR REPLACE VIEW myv5
AS
SELECT * FROM myv3;
更新
SELECT * FROM myv5;
UPDATE myv5 SET 最高工资=10000 WHERE department_id=60;
⑥where子句的子查询引用了from子句中的表
CREATE OR REPLACE VIEW myv6
AS
SELECT last_name,email,salary
FROM employees
WHERE employee_id IN(
SELECT manager_id
FROM employees
WHERE manager_id IS NOT NULL
);
更新
SELECT * FROM myv6;
UPDATE myv6 SET salary=10000 WHERE last_name = 'k_ing';
16.7 视图习题
一、创建视图emp_v1,要求查询电话号码以‘011’开头的员工姓名和工资、邮箱
CREATE OR REPLACE VIEW emp_v1
AS
SELECT last_name,salary,email
FROM employees
WHERE phone_number LIKE '011%';
二、创建视图emp_v2,要求查询部门的最高工资高于12000的部门信息
CREATE OR REPLACE VIEW emp_v2
AS
SELECT MAX(salary) mx_dep,department_id
FROM employees
GROUP BY department_id
HAVING MAX(salary)>12000;
SELECT d.*,m.mx_dep
FROM departments d
JOIN emp_v2 m
ON m.department_id = d.`department_id`;