剑指 Offer 24. 反转链表

 

 

 

class Solution {
    public ListNode reverseList(ListNode head) {
        ListNode cur = head, pre = null;
        while(cur != null) {
            ListNode tmp = cur.next; // 暂存后继节点 cur.next
            cur.next = pre;          // 修改 next 引用指向
            pre = cur;               // pre 暂存 cur
            cur = tmp;               // cur 访问下一节点
        }
        return pre;
    }
}

大佬解析：

https://leetcode.cn/problems/fan-zhuan-lian-biao-lcof/solution/jian-zhi-offer-24-fan-zhuan-lian-biao-die-dai-di-2/