通过ajax从jsp页面传输数据到web层,并从web层返回数据给jsp页面
jsp中ajax代码:
1 $.ajax({ 2 var id = $("#studentid").val();//获取标签中的学生id 3 url:'${pageContext.request.contextPath}/student/stu_delStudent.action?studentid='+id, 4 data:'', 5 type:'POST', 6 dataType:'json', 7 async:false, 8 success:function(data){ 9 alert(data.message); 10 } 11 12 });
action中的代码:
1 public class StudentAction extends ActionSupport{ 2 private Student student; 3 public Student getStudent() { 4 return student; 5 } 6 public void setStudent(Student student) { 7 this.student = student; 8 } 9 10 @Resource 11 private StudentService studentService; 12 13 public String delStudent() throws Exception{ 14 //接收请求数据 15 int studentid = ServletActionContext.getRequest().getParameter("studentid"); 16 studentSerivce.delByStudentId(studentid); 17 //创建一个JSON对象 18 JSONObject json = new JSONObject(); 19 json.put(“message",删除成功");//将返回信息保存在JSON对象中 20 HttpServletResponse response = ServletActionContext.getResponse(); 21 //设置响应编码格式,防止乱码 22 response.setContentType("text/html;charset=UTF-8"); 23 //将数据以json格式响应给ajax 24 response.getWriter().write(json.toString()); 25 26 return null; 27 } 28 }
不能只满足于写完代码运行结果正确就完事,时常考虑如何让代码更加简练更加容易维护、容易扩展和复用,只有这样才可以真正得到提高
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