挣值分析代码(简陋版)

具体代码

import matplotlib.pyplot as plt
import numpy as np
import matplotlib
matplotlib.use('TkAgg')

from pylab import mpl
mpl.rcParams['font.sans-serif'] = ['Microsoft YaHei'] # 指定默认字体:解决plot不能显示中文问题
mpl.rcParams['axes.unicode_minus'] = False # 解决保存图像是负号'-'显示为方块的问题


# 设定函数进行计算
def SV(EV, PV):
    return EV-PV

def CV(EV,AC):
    return EV-AC

def SPI(EV,PV):
    return EV/PV

def CPI(EV,AC):
    return EV/AC

def TEAC(SAC,SPI):
    return SAC/SPI

def EAC(BAC,CPI):
    return BAC/CPI

# 存储用得上的数据
PV1 = [30, 10, 15, 5]
PV2 = [70, 0, 10, 10]

AC1 = [10, 16, 8]
AC2 = [0, 10, 10]

EV1 = [30, 80, 100]
EV2 = [0, 10, 25]

# 第一周
pv1 = PV1[1]+PV2[1]
ac1 = AC1[0]+AC2[0]
ev1 = PV1[0]*EV1[0]*0.01+PV2[0]*EV2[0]*0.01
sv1 = SV(ev1, pv1)
cv1 = CV(ev1, ac1)

spi1 = SPI(ev1, pv1)
cpi1 = CPI(ev1, ac1)

teac1 = TEAC(10, spi1)
eac1 = EAC(170, cpi1)


# 第二周
pv2 = PV1[2]+PV2[2]+pv1
ac2 = AC1[1]+AC2[1]+ac1
ev2 = PV1[0]*EV1[1]*0.01+PV2[0]*EV2[1]*0.01


sv2 = SV(ev2, pv2)
cv2 = CV(ev2, ac2)

spi2 = SPI(ev2, pv2)
cpi2 = CPI(ev2, ac2)

teac2 = TEAC(10, spi2)
eac2 = EAC(170, cpi2)


# 第三周
pv3 = PV1[3]+PV2[3]+pv2
ac3 = AC1[2]+AC2[2]+ac2
ev3 = PV1[0]*EV1[2]*0.01+PV2[0]*EV2[2]*0.01


sv3 = SV(ev3, pv3)
cv3 = CV(ev3, ac3)

spi3 = SPI(ev3, pv3)
cpi3 = CPI(ev3, ac3)

teac3 = TEAC(10, spi3)
eac3 = EAC(170, cpi3)


# 将得到的数据存储为列表
pvList = []
pvList.append(pv1)
pvList.append(pv2)
pvList.append(pv3)

acList = []
acList.append(ac1)
acList.append(ac2)
acList.append(ac3)

evList = []
evList.append(ev1)
evList.append(ev2)
evList.append(ev3)

x_data = ['第一周', '第二周', '第三周']

plt.plot(x_data, pvList, 'p--', alpha=0.5, linewidth=1, label='PV')  # 'bo-'表示蓝色实线,数据点实心原点标注
## plot中参数的含义分别是横轴值,纵轴值,线的形状('s'方块,'o'实心圆点,'*'五角星   ...,颜色,透明度,线的宽度和标签 ,
plt.plot(x_data, acList, '*--', alpha=0.5, linewidth=1, label='AC')
plt.plot(x_data, evList, '+--', alpha=0.5, linewidth=1, label='EV')

plt.legend()  # 显示上面的label
plt.xlabel('时间/周')  # x_label
plt.ylabel('值')  # y_label

# plt.ylim(-1,1)#仅设置y轴坐标范围
plt.show()

效果展示

posted @ 2024-04-02 19:14  yesyes1  阅读(57)  评论(0编辑  收藏  举报