1028 List Sorting

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:

Each input file contains one test case. For each case, the first line contains two integers N (≤) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1:

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60

Sample Output 1:

000001 Zoe 60
000007 James 85
000010 Amy 90

Sample Input 2:

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98

Sample Output 2:

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60

Sample Input 3:

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90

Sample Output 3:

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

/*
    Name:
    Copyright:
    Author:  流照君
    Date: 2019/8/14 14:46:37
    Description:
*/
#include <iostream>
#include<string>
#include <algorithm>
#include <vector>
#define inf 100100
using namespace std;
typedef long long ll;
struct student{
	int sno;
	string name;
	int score;
};
student s[inf];
bool cmp1(student a,student b)
{
	 return a.sno<b.sno;
}
bool cmp2(student a,student b)
{
	if(a.name!=b.name)
	 return a.name<b.name;
	 else
	 return a.sno<b.sno; 
}
bool cmp3(student a,student b)
{
	if(a.score!=b.score)
	 return a.score<b.score;
	 else
	 return a.sno<b.sno;
}
int main(int argc, char** argv)
{
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
    int n,c;
    cin>>n>>c;
    for(int i=0;i<n;i++)
    cin>>s[i].sno>>s[i].name>>s[i].score;
    if(c==1)
    {
    	sort(s,s+n,cmp1);
	}
	else if(c==2)
	{
		sort(s,s+n,cmp2);
	}
	else if(c==3)
	{
		sort(s,s+n,cmp3);
	}
	for(int i=0;i<n;i++)
	{
		printf("%06d ",s[i].sno);
		cout<<s[i].name<<" ";
		printf("%d",s[i].score);
		printf("\n");
	}
    return 0;
}

　　很简单结构体排序，重写cmp就行