通过传入从START_YEAR到当前时间的秒数,计算当前日期与时间。
#define START_YEAR (1985) #define SECOND_DAY (86400) //60*60*24 #define SECOND_HOUR (3600) //60*60 #define SECOND_MIN (60) //60 const unsigned short int mon_yday[][13] = { /* Normal years. */ { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365 }, /* Leap years. */ { 0, 31, 60, 91, 121, 152, 182, 213, 244, 274, 305, 335, 366 } }; //判断一个年份是否为闰年,是就返回1,不是就返回0 inline int isLeapYear(int year) { return( (year%4 == 0 && year%100 != 0) || (year%400 == 0) ); } //获取一年的天数 inline int getDaysForYear(int year) { return (isLeapYear(year)?366:365); } //根据秒数计算日期 void getDate(int second, int& year, int& month, int& day) { int days = second / SECOND_DAY; int curYear = START_YEAR; int leftDays = days; //calc year int daysCurYear = getDaysForYear(curYear); while (leftDays >= daysCurYear) { leftDays -= daysCurYear; curYear++; daysCurYear = getDaysForYear(curYear); } year = curYear; //calc month and day int isLeepYear = isLeapYear(curYear); for (int i = 1; i < 13; i++) { if (leftDays < mon_yday[isLeepYear][i]) { month = i; day = leftDays - mon_yday[isLeepYear][i-1] + 1; break; } } } //计算时间 void getTime(int seconds, int& hour, int& minute, int& second) { int leftSeconds = seconds % SECOND_DAY; hour = leftSeconds / SECOND_HOUR; minute = (leftSeconds % SECOND_HOUR) / SECOND_MIN; second = leftSeconds % SECOND_MIN; }