servlet中url-pattern /与/* 的区别
web.xml
<?xml version="1.0" encoding="UTF-8"?> <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <context-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:applicationContext.xml</param-value> </context-param> <listener> <display-name>contextLoaderListener</display-name> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <servlet> <servlet-name>springMVC</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <!--<init-param>--> <!--<param-name>contextConfigLocation</param-name>--> <!--<param-value>classpath:springMVC-servlet.xml</param-value>--> <!--</init-param>--> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>springMVC</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> </web-app>
java类 Demo
@Controller public class Demo { @RequestMapping("/test") public String test(){ System.out.println("hehe"); return "hehe"; } }
WEB-INF下定义了hehe.jsp 显示hello world
启动tomcat,访问http://localhost:8080/test
报错,提示09-Jan-2018 15:44:37.805 WARNING [http-nio-8080-exec-6] org.springframework.web.servlet.PageNotFound.noHandlerFound No mapping found for HTTP request with URI [/WEB-INF/hehe.jsp] in DispatcherServlet with name 'springMVC'
查看别人资料,将
<url-pattern>/*</url-pattern>
修改为
<url-pattern>/</url-pattern>
发现可以正常访问:
原因分析:
根据前人所述,使用 /* 会导致返回的hehe.jsp再次进入DispatcherServlet,进而找不到与其匹配的路径,而通过错误提示可知路径为/WEB-INF/hehe.jsp,为了验证这个猜测,我在Demo类又加了一个与之对应的匹配
@Controller public class Demo { @RequestMapping("/test") public String test(){ System.out.println("hehe"); return "hehe"; } @RequestMapping("/WEB-INF/hehe.jsp") public String test2(){ System.out.println("hehe2"); return "hehe"; } }
以debug模式运行,发现果然进行了二次匹配~
如图,报错信息明显:循环路径