IntelliJ IDEA 2017版 SpringBoot的Json字符串返回

一、说明

      SpringBoot框架已经自动封装好json字符串解析,所以我们只需要用它的注解来返回操作就可以了.

二、实战

     1、书写一个实体类User，设置属性id和name     

package com.json;

/**
 * Created by liuya on 2018-01-17.
 */
public class UserPoJo
{
    private int userId;
    private String userName;

    public int getUserId() {
        return userId;
    }

    public void setUserId(int userId) {
        this.userId = userId;
    }

    public String getUserName() {
        return userName;
    }

    public void setUserName(String userName) {
        this.userName = userName;
    }

    @Override
    public String toString() {
        return "UserPoJo{" +
                "userId=" + userId +
                ", userName='" + userName + '\'' +
                '}';
    }
}

    2、书写开启服务器的代码（SpringBoot框架自带一个测试服务器）

package com.json;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;


@SpringBootApplication
public class SpringboothelloApplication {


    public static void main(String[] args) {
        SpringApplication.run(SpringboothelloApplication.class, args);
    }



}

   3、书写controller返回json的代码

package com.json;

import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;

/**
 * Created by liuya on 2018-01-16.
 *
 *  测试用的一个例子
 */


@RestController
public class ControllerJson {

    @RequestMapping("user")
    public UserPoJo hello(){
        //实体类赋值
        UserPoJo userPoJo  = new UserPoJo();
        userPoJo.setUserId(111);
        userPoJo.setUserName("王小二");
        //返回实体类
        return userPoJo;
    }
}

   4、启动服务器的代码，生成如图

     

5、浏览器测试