40 字符串排序
题目:字符串排序
分析:
根据已经的字符串,先进行第一个字母排序,在进行第二个字母的排序
1 public class _040PrintString { 2 3 public static void main(String[] args) { 4 printString(); 5 } 6 7 private static void printString() { 8 int N = 5; 9 String temp = null; 10 String[] string = new String[N]; 11 string[0] = "matter"; 12 string[1] = "state"; 13 string[2] = "solid"; 14 string[3] = "liquid"; 15 string[4] = "gas"; 16 17 for (int i = 0; i < N; i++) { 18 for (int j = i + 1; j < N; j++) { 19 if (compare(string[i], string[j]) == false) { 20 temp = string[i]; 21 string[i] = string[j]; 22 string[j] = temp; 23 } 24 } 25 } 26 27 for (int i = 0; i < N; i++) { 28 System.out.println(string[i]); 29 } 30 } 31 32 public static boolean compare(String s1, String s2) { 33 boolean result = true; 34 35 for (int i = 0; i < s1.length() && i < s2.length(); i++) { 36 if (s1.charAt(i) > s2.charAt(i)) { 37 result = false; 38 break; 39 } else if (s1.charAt(i) < s2.charAt(i)) { 40 result = true; 41 break; 42 } else { 43 if (s1.length() < s2.length()) { 44 result = true; 45 } else { 46 result = false; 47 } 48 } 49 } 50 51 return result; 52 } 53 }
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