40 字符串排序

题目:字符串排序
分析:
      根据已经的字符串,先进行第一个字母排序,在进行第二个字母的排序

    public class _040PrintString {

    public static void main(String[] args) {
        printString();
    }

    private static void printString() {
        int N = 5;
        String temp = null;
        String[] string = new String[N];
        string[0] = "matter";
        string[1] = "state";
        string[2] = "solid";
        string[3] = "liquid";
        string[4] = "gas";

        for (int i = 0; i < N; i++) {
            for (int j = i + 1; j < N; j++) {
                if (compare(string[i], string[j]) == false) {
                    temp = string[i];
                    string[i] = string[j];
                    string[j] = temp;
                }
            }
        }

        for (int i = 0; i < N; i++) {
            System.out.println(string[i]);
        }
    }

    public static boolean compare(String s1, String s2) {
        boolean result = true;

        for (int i = 0; i < s1.length() && i < s2.length(); i++) {
            if (s1.charAt(i) > s2.charAt(i)) {
                result = false;
                break;
            } else if (s1.charAt(i) < s2.charAt(i)) {
                result = true;
                break;
            } else {
                if (s1.length() < s2.length()) {
                    result = true;
                } else {
                    result = false;
                }
            }
        }

        return result;
    }
}