CF271 A. Beautiful Year

A. Beautiful Year

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.

Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.

Input

The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.

Output

Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.

Sample test(s)

input

1987

output

2013

input

2013

output

2014

 

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
int judge(int n)
{
  int a[10];
  memset(a, 0, sizeof(a));
  int k = 1;
  for (int i = 0; i < 4; ++i)
  {
    if (a[(n/k)%10] == 0)
    {
      a[(n/k)%10] = 1;
    }
    else return 0;
    k *= 10;
  }
  return 1;
}
int main(void)
{
  int y;
  while (~scanf("%d", &y))
  {
    for (int i = 1; ; ++i)
    {
      if (judge(y+i))
      {
        printf("%d\n", y+i); break;
      }
    }
  }

  return 0;
}

天下没有水题……

先看清题目意思，然后认真快速敲代码就可以了。

意思是给出一个年份，求出严格比它大的，并且这个年份的四个数字互不相同的最小年份，年份的范围是[1000, 9000]