重集合中找出最相近的一个数字

1.网友提供代码

        private static decimal getNear(List<decimal> num, decimal target)
        {
            List<decimal> c = new List<decimal>();
            foreach (var item in num)
            {
                c.Add(Math.Abs(item - target));
            }
            c.Sort();
            for (int i = 0; i < num.Count; i++)
            {
                if (Math.Abs(num[i] - target) == c[0])
                {
                    return num[i];
                }
            }
            return 0;
        }

2.改进后的代码

        private static decimal GetNear(List<decimal> collection, decimal target)
        {
            return collection.FirstOrDefault(item => Math.Abs(item - target) == collection.Select(s => Math.Abs(s - target)).OrderBy(o => o).First());
        }