冒泡排序和二分查找算法

1.冒泡排序:

    

    private static void bubbleSort(int[] arr) {
        for(int j=0;j<arr.length-1;j++){  //外层循环 控制排序的次数
            for(int m=0;m<arr.length-1-j;m++){  //内层循环 控制每一趟排序多少次
                    if(arr[m]>arr[m+1]){
                        int temp = arr[m];
                        arr[m] = arr[m+1];
                        arr[m+1] = temp;
                    }
            }
        }
    }

 

2.二分查找

  二分查找算法分为循环查找和递归查找

  01.循环查找

   

 /**
     *
     * @param arr 数组
     * @param x  查找值
     * @return   查到的值
     */

    public static int binarySearch(int[] arr, int x) {

        int low= 0;
        int high = arr.length-1;

        while (low <= high){
            int middle = (low+high)/2;
            if(x==arr[middle]){
                return arr[middle];
            }else if(x < arr[middle]){
                high = middle - 1;
            }else if(x > arr[middle]){
                low = middle + 1;
            }


        }
        return -1;
    }

 

02.递归查找

  

/**
     * 递归查找
     * @param arr  数组
     * @param key  需要查询的值
     * @param start 开始上标
     * @param end   开始下标
     * @return  找到的值
     */
    public static int binarySearch(int[] arr,int key,int start,int end){

        if(start>end||start<0){
            return -1;
        }else{

            int middle = (start+end)/2;

            if(key == arr[middle]){
                return key;
            }

            if(key < arr[middle]){
                return  binarySearch(arr,key,start,middle-1);
            }

            if(key>arr[middle]){
                return  binarySearch(arr,key,middle+1,end);
            }

            return -1;

        }
    }

 

测试:

  

 public static void main(String[] args) {
        int[] arr = { 6, 12, 33, 87, 90, 97, 108, 561 };
        System.out.println("循环查找:" + binarySearch(arr, 87));
        System.out.println("递归查找:"+binarySearch(arr,87,0,arr.length-1));
    }

 

输出结果:

循环查找:87
递归查找:87

Process finished with exit code 0

  

 

 

 

posted on 2019-01-28 13:48  天天xiangshang  阅读(1039)  评论(0编辑  收藏  举报

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