摘要: SELECT * FROM task a, (SELECT id, name, addtime FROM task_step j, (SELECT id, name, max(addtime) addtime FROM task_step GROUP BY id) q WHERE j.id=q.id 阅读全文
posted @ 2022-07-01 11:28 Liu66~ 阅读(534) 评论(0) 推荐(0) 编辑