format

---恢复内容开始---

tp1='i am {},age{},{}'.format("seven",18,'alex')#不一一对应会报错
print(tp1)

输出

i am seven,age18,alex
tp2='i am {},age{},{}'.format("seven",18)
print(tp2)

输出报错

IndexError: tuple index out of range
tp2='i am {2},age{1},{0}'.format("seven",18,'alex')
print(tp2)

输出

i am alex,age18,seven
tp2='i am {1},age{1}'.format("seven",18,'alex')
print(tp2)

输出

i am 18,age18
tp2='i am {name},age{age},really{name}'.format(name="seven",age=18)
print(tp2)

输出

i am seven,age18,reallyseven
tp2='i am {name},age{age},really{name}'.format(**{'name':"seven",'age':18})
print(tp2)

输出

i am seven,age18,reallyseven
tp1='i am {0[0]},age{0[1]},really{0[2]}'.format([1,2,3],[11,22,33])
print(tp1)

输出

i am 1,age2,really3
tp1='i am {:s},age{:d},really{:f}'.format("seven",18,88.7)
print(tp1)

输出

i am seven,age18,really88.700000
tp1='i am {name:s},age{age:d}'.format(name="seven",age=18)
print(tp1)

输出

i am seven,age18
tp1 = 'i am {name:s},age{age:d}'.format(**{'name': "seven", 'age': 18})
print(tp1)

输出

i am seven,age18

:b二进制  :o八进制  :d整  :x十六进制  :%显示百分比(默认小数点后六位)

多了可以少了不行

tp1 = 'nambers:{:b},{:o},{:d},{:x},{:x},{:%}'.format(15,15,15,15,15,15.87623,2)
print(tp1)

输出

nambers:1111,17,15,f,f,1587.623000%

 

 

---恢复内容结束---

 

posted @ 2019-01-14 09:43  流水众生  阅读(228)  评论(0编辑  收藏  举报