如何使用Python写一个Docker远程管理工具_API数据的json格式化输出

一、前言

最近想自己手动写一个基于DockerAPI的远程管理工具，本系列文章将一直记录编写过程中遇到的问题及解决方法

 相关链接：

Dokcer远程访问实现类api功能

二、面临的问题

2.1、API数据混乱

一开始我写的代码是这样的

import json
import requests
url = 'http://1.1.1.11:2375/containers/json?all=1'
r = requests.get(url)
decoded = json.dumps(r.text)
print(decoded)

执行结果是这样的

而我希望得到的数据是这样的

root@ubuntu20:~# curl http://1.1.1.11:2375/containers/json  | python3 -m json.tool
  % Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
                                 Dload  Upload   Total   Spent    Left  Speed
100  1194  100  1194    0     0  1166k      0 --:--:-- --:--:-- --:--:-- 1166k
[
    {
        "Id": "f8026170e99a16c5a3aa4da1a80f7c66babcc0b3652b507dd44efe0f8125388e",
        "Names": [
            "/cool_kalam"
        ],
        "Image": "centos",
        "ImageID": "sha256:470671670cac686c7cf0081e0b37da2e9f4f768ddc5f6a26102ccd1c6954c1ee",
        "Command": "/bin/bash",
        "Created": 1593242626,
        "Ports": [],
        "Labels": {
            "org.label-schema.build-date": "20200114",
            "org.label-schema.license": "GPLv2",
            "org.label-schema.name": "CentOS Base Image",
            "org.label-schema.schema-version": "1.0",
            "org.label-schema.vendor": "CentOS",
            "org.opencontainers.image.created": "2020-01-14 00:00:00-08:00",
            "org.opencontainers.image.licenses": "GPL-2.0-only",
            "org.opencontainers.image.title": "CentOS Base Image",
            "org.opencontainers.image.vendor": "CentOS"
        },
        "State": "running",
        "Status": "Up 12 minutes",
        "HostConfig": {
            "NetworkMode": "default"
        },
        "NetworkSettings": {
            "Networks": {
                "bridge": {
                    "IPAMConfig": null,
                    "Links": null,
                    "Aliases": null,
                    "NetworkID": "fe0b15e170623843c6ddaca8103cee0071aba3c18cc8f02cc14a19847f7ecca4",
                    "EndpointID": "0c06037c7b2b4bf4957f02906d3764f0dbfbcea9cc2423385b7eea94d2c7a504",
                    "Gateway": "172.17.0.1",
                    "IPAddress": "172.17.0.2",
                    "IPPrefixLen": 16,
                    "IPv6Gateway": "",
                    "GlobalIPv6Address": "",
                    "GlobalIPv6PrefixLen": 0,
                    "MacAddress": "02:42:ac:11:00:02",
                    "DriverOpts": null
                }
            }
        },
        "Mounts": []
    }
]

三、解决方法

其实只需要把text改成json即可

import json
import requests
url = 'http://1.1.1.11:2375/containers/json?all=1'
r = requests.get(url)
decoded = json.dumps(r.json(), indent=4)
print(decoded)

然后得到的结果是这样的

下一篇写如何从json数据里面取得自己想要的数据