LeetCode 459. Repeated Substring Pattern
Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. You may assume the given string consists of lowercase English letters only and its length will not exceed 10000.
Example 1:
Input: "abab" Output: True Explanation: It's the substring "ab" twice.
Example 2:
Input: "aba" Output: False
Example 3:
Input: "abcabcabcabc" Output: True Explanation: It's the substring "abc" four times. (And the substring "abcabc" twice.)
【题目分析】
判断一个字符串是否是由某个子串重复多次构成。
【思路】
1. 子串至少重复两次
2. 从字符串的头部取长度范围为1~str.length()/2的子串,用正则表达式来进行判断。
【java代码】
1 public class Solution { 2 public boolean repeatedSubstringPattern(String str) { 3 if(str == null || str.length() < 2) return false; 4 5 boolean result = false; 6 for(int i = 1; i <= str.length()/2; i++) { 7 if(str.length()%i != 0) continue; 8 String regex = "("+str.substring(0,i)+")" + "+"; 9 result = result | str.matches(regex); 10 } 11 return result; 12 } 13 }