linux中实现将多个连续的字符拆分为单个字符

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root@DESKTOP-1N42TVH:/home/test# ls
outcome.map
root@DESKTOP-1N42TVH:/home/test# cat outcome.map  ## 测试数据
1s64199.1055910
1OAR19_64675012.1085204
1OAR19_64715327.10122948
1OAR19_64803054.10203750
1DU281551_498.10312707
1s18939.10356863
root@DESKTOP-1N42TVH:/home/test# sed 's/./ &/g' outcome.map  ##将每一个字符替换为空格+字符
 1 s 6 4 1 9 9 . 1 0 5 5 9 1 0
 1 O A R 1 9 _ 6 4 6 7 5 0 1 2 . 1 0 8 5 2 0 4
 1 O A R 1 9 _ 6 4 7 1 5 3 2 7 . 1 0 1 2 2 9 4 8
 1 O A R 1 9 _ 6 4 8 0 3 0 5 4 . 1 0 2 0 3 7 5 0
 1 D U 2 8 1 5 5 1 _ 4 9 8 . 1 0 3 1 2 7 0 7
 1 s 1 8 9 3 9 . 1 0 3 5 6 8 6 3
root@DESKTOP-1N42TVH:/home/test# sed 's/./ &/g' outcome.map | sed 's/^.//'  ## 删除文本开头的字符
1 s 6 4 1 9 9 . 1 0 5 5 9 1 0
1 O A R 1 9 _ 6 4 6 7 5 0 1 2 . 1 0 8 5 2 0 4
1 O A R 1 9 _ 6 4 7 1 5 3 2 7 . 1 0 1 2 2 9 4 8
1 O A R 1 9 _ 6 4 8 0 3 0 5 4 . 1 0 2 0 3 7 5 0
1 D U 2 8 1 5 5 1 _ 4 9 8 . 1 0 3 1 2 7 0 7
1 s 1 8 9 3 9 . 1 0 3 5 6 8 6 3