c语言 7-5

编写inverse_n函数，返回将无符号整数x的第pos为开始的n位取反后的值。

1、

#include <stdio.h>

unsigned inverse_n(unsigned x, int pos, int n)
{
    int i;
    for(i = pos; i <= pos + n - 1; i++)
    {
        if(x >> i & 1U)
            x = (x & (~(1 << i)));
        else
            x = (x | 1 << i);
    }
    return x;
}

int main(void)
{
    unsigned x;
    int pos, i;
    puts("please input three integers.");
    printf("x = "); scanf("%u", &x);
    printf("pos = "); scanf("%d", &pos);
    printf("i = "); scanf("%d", &i);
    
    printf("result: %u\n", inverse_n(x, pos, i));
    return 0;
}