python中返回列表中元素的索引

 

>>> test1 = ["aaa","bbb","aaa","ccc","aaa","aaa","ddd","aaa","ccc"]
>>> test1.index("aaa")   ## 返回元素的首个索引
0
>>> test1.index("bbb")
1
>>> test1.index("ccc")
3
>>> test1.count("aaa")
5
>>> a = test1.count("aaa")
>>> b = -1
>>> for i in range(a):        ## 返回元素的所有索引
    b = test1.index("aaa",b+1,len(test1))
    print("aaa:",b)

    
aaa: 0
aaa: 2
aaa: 4
aaa: 5
aaa: 7
>>> test1
['aaa', 'bbb', 'aaa', 'ccc', 'aaa', 'aaa', 'ddd', 'aaa', 'ccc']

 

posted @ 2020-12-19 00:08  小鲨鱼2018  阅读(2133)  评论(0编辑  收藏  举报