LCS算法改进

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public static void Lcs_Length(String X,String Y,int c[][])
    {
        X=" "+X;
        Y=" "+Y;
        for(int i=1;i<X.length();i++)
        {
            c[i][0]=0;
        }
        for(int j=0;j<Y.length();j++)
        {
            c[0][j]=0;
        }
        for(int i=1;i<X.length();i++)
        {
            for(int j=1;j<Y.length();j++)
            {
                if(X.charAt(i)==Y.charAt(j))
                {
                    c[i][j]=c[i-1][j-1]+1;
                }
                else if(c[i-1][j]>=c[i][j-1])
                {
                    c[i][j]=c[i-1][j];
                }
                else
                {
                    c[i][j]=c[i][j-1];
                }
            }
        }
    }
    public static void Print_Lcs(int c[][],String X,int i,int j)
    {
        if(i==0||j==0)
            return;
        if(c[i][j]==c[i-1][j])
        {
            Print_Lcs(c,X,i-1,j);
        }
        else if(c[i][j]==c[i][j-1])
        {
            Print_Lcs(c,X,i,j-1);
        }
        else
        {
            Print_Lcs(c,X,i-1,j-1);
            System.out.print(X.charAt(i-1)+" ");
        }
             
    }
    public static void main(String[] args)
    {
 
        String X="ABCBDAB";
        String Y="BDCABA";
        int c[][]=new int[X.length()+1][Y.length()+1];
        Lcs_Length(X,Y,c);
        for(int i=0;i<c.length;i++)
        {
            for(int j=0;j<c[i].length;j++)
                System.out.print(c[i][j]+" ");
            System.out.println();
        }
        Print_Lcs(c,X,X.length(),Y.length());
    }

 

posted @   liuhg  阅读(432)  评论(0编辑  收藏  举报
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