【java基础】冒泡排序 正序倒叙排序 【一眼就会系列】

		//本节课:1、数组冒泡排序:倒序、正序
        //1、冒泡正序:
        int num[] = {345, 2, 3, 777, 34, 233, 97, 30};
        for (int i = 0; i < num.length; i++) {
            for (int t = 0; t < num.length - 1 - i; t++) {
                if (num[t] > num[t + 1]) {
                    int x = num[t];
                    num[t] = num[t + 1];
                    num[t + 1] = x;

                }
            }
        }
        System.out.println(Arrays.toString(num));
        //输出:[2, 3, 30, 34, 97, 233, 345, 777]
		
		
		
		//2、冒泡倒序:
        int num[] = {345, 2, 3, 777, 34, 233, 97, 30};
        for (int i = 0; i < num.length; i++) {
            for (int t = 0; t < num.length - 1 - i; t++) {
                if (num[t] < num[t + 1]) {
                    int x = num[t];
                    num[t] = num[t + 1];
                    num[t + 1] = x;

                }
            }
        }
        System.out.println(Arrays.toString(num));
		//输出:[777, 345, 233, 97, 34, 30, 3, 2]
		
		
		//注意:
		//1、(num[t] > num[t + 1])为正序。(num[t] < num[t + 1])为倒序;
		//2、是加数字1不是i.
		
		
		//正序输出:
		     String str = "";
        for (int i = 0; i < 7; i++) {
            str += "*";
            System.out.println(str);
        }
		
		/*
        //正序输出:		
        *
        **
        ***
        ****
        *****
        ******
        *******
		
		*/
		
		
		  //倒序输出
        for (int i = 7; i >=1 ; i--) {
            String strs="";
            for(int t=0;t<i;t++){
                strs+="*";
            }
            System.out.println(strs);
        }
		
        /*		
        倒序输出:		
        *******
        ******
        *****
        ****
        ***
        **
        *



        */

  

posted @ 2023-09-17 13:35  刘贵庆  阅读(185)  评论(0编辑  收藏  举报