201771010113 李婷华 《面向对象程序设计(Java)》第十七周总结

一.理论知识部分

 Java 的线程调度采用优先级策略:优先级高的先执行,优先级低的后执行;多线程系统会自动为每个线程分配一个优先级,缺省时,继承其父类的优先级; 任务紧急的线程,其优先级较高; 同优先级的线程按“先进先出”的队列原则。

调用setPriority(int a)重置当前线程的优先级,a取值可以是前述的三个静态量。调用getPriority()获得当前线程优先级。

多线程并发运行不确定性问题解决方案:引入线程同步机制,使得另一线程要使用该方法,就只能等待。

在Java中解决多线程同步问题的方法有两种:J ava SE 5.0中引入ReentrantLock类。 在共享内存的类方法前加synchronized修饰符。

有关锁对象和条件对象的关键要点:锁用来保护代码片段,保证任何时刻只能有一个线程执行被保护的代码。锁管理试图进入被保护代码段的线程。锁可拥有一个或多个相关条件对象。每个条件对象管理那些已经进入被保护的代码 段但还不能运行的线程。

synchronized关键字作用: 某个类内方法用synchronized 修饰后,该方法被称为同步方法;只要某个线程正在访问同步方法,其他线程欲要访问同步方法就被阻塞,直至线程从同 步方法返回前唤醒被阻塞线程,其他线程方可能进入同步方法。

在同步方法中使用wait()、notify 和notifyAll()方法:一个线程在使用的同步方法中时,可能根据问题的需要,必须使用wait()方法使本线程等待,暂时让出CPU的使用权,并允许其它线程使用这个同步方法。线程如果用完同步方法,应当执行notifyAll()方 法通知所有由于使用这个同步方法而处于等待的线程结束等待。

二.实验部分

1、实验目的与要求

(1) 掌握线程同步的概念及实现技术; 

(2) 线程综合编程练习

2、实验内容和步骤

实验1:测试程序并进行代码注释。

测试程序1:

l 在Elipse环境下调试教材651页程序14-7,结合程序运行结果理解程序;

l 掌握利用锁对象和条件对象实现的多线程同步技术。

 1 package synch;
 2 
 3 /**
 4  * This program shows how multiple threads can safely access a data structure.
 5  * @version 1.31 2015-06-21
 6  * @author Cay Horstmann
 7  */
 8 public class SynchBankTest
 9 {
10    public static final int NACCOUNTS = 100;
11    public static final double INITIAL_BALANCE = 1000;
12    public static final double MAX_AMOUNT = 1000;
13    public static final int DELAY = 10;
14    
15    public static void main(String[] args)
16    {
17       Bank bank = new Bank(NACCOUNTS, INITIAL_BALANCE);
18       for (int i = 0; i < NACCOUNTS; i++)
19       {
20          int fromAccount = i;
21          Runnable r = () -> {
22             try
23             {
24                while (true)
25                {
26                   int toAccount = (int) (bank.size() * Math.random());
27                   double amount = MAX_AMOUNT * Math.random();
28                   bank.transfer(fromAccount, toAccount, amount);
29                   Thread.sleep((int) (DELAY * Math.random()));//随机生成时间,使正在执行的线程休眠
30                }
31             }
32             catch (InterruptedException e)
33             {
34             }            
35          };
36          Thread t = new Thread(r);
37          t.start();//开始线程
38       }
39    }
40 }
SynchBankTest
 1 package synch;
 2 
 3 import java.util.*;
 4 import java.util.concurrent.locks.*;
 5 
 6 /**
 7  * A bank with a number of bank accounts that uses locks for serializing access.
 8  * @version 1.30 2004-08-01
 9  * @author Cay Horstmann
10  */
11 public class Bank
12 {
13    private final double[] accounts;
14    private Lock bankLock;
15    private Condition sufficientFunds;
16 
17    /**
18     * Constructs the bank.
19     * @param n the number of accounts
20     * @param initialBalance the initial balance for each account
21     */
22    public Bank(int n, double initialBalance)
23    {
24       accounts = new double[n];
25       Arrays.fill(accounts, initialBalance);
26       bankLock = new ReentrantLock();
27       sufficientFunds = bankLock.newCondition();
28    }
29 
30    /**
31     * Transfers money from one account to another.
32     * @param from the account to transfer from
33     * @param to the account to transfer to
34     * @param amount the amount to transfer
35     */
36    public void transfer(int from, int to, double amount) throws InterruptedException
37    {
38       bankLock.lock();//使用锁对象,获取锁
39       try
40       {
41          while (accounts[from] < amount)
42             sufficientFunds.await();
43          System.out.print(Thread.currentThread());
44          accounts[from] -= amount;
45          System.out.printf(" %10.2f from %d to %d", amount, from, to);
46          accounts[to] += amount;
47          System.out.printf(" Total Balance: %10.2f%n", getTotalBalance());
48          sufficientFunds.signalAll();//唤醒所有线程
49       }
50       finally
51       {
52          bankLock.unlock();//释放锁
53       }
54    }
55 
56    /**
57     * Gets the sum of all account balances.
58     * @return the total balance
59     */
60    public double getTotalBalance()
61    {
62       bankLock.lock();
63       try
64       {
65          double sum = 0;
66 
67          for (double a : accounts)
68             sum += a;
69 
70          return sum;
71       }
72       finally
73       {
74          bankLock.unlock();
75       }
76    }
77 
78    /**
79     * Gets the number of accounts in the bank.
80     * @return the number of accounts
81     */
82    public int size()
83    {
84       return accounts.length;
85    }
86 }
Bank

测试程序2:

l 在Elipse环境下调试教材655页程序14-8,结合程序运行结果理解程序;

l 掌握synchronized在多线程同步中的应用。

 1 package synch2;
 2 
 3 import java.util.*;
 4 
 5 /**
 6  * A bank with a number of bank accounts that uses synchronization primitives.
 7  * @version 1.30 2004-08-01
 8  * @author Cay Horstmann
 9  */
10 public class Bank
11 {
12    private final double[] accounts;
13 
14    /**
15     * Constructs the bank.
16     * @param n the number of accounts
17     * @param initialBalance the initial balance for each account
18     */
19    public Bank(int n, double initialBalance)
20    {
21       accounts = new double[n];
22       Arrays.fill(accounts, initialBalance);
23    }
24 
25    /**
26     * Transfers money from one account to another.
27     * @param from the account to transfer from
28     * @param to the account to transfer to
29     * @param amount the amount to transfer
30     */
31    //使用synchronized修饰符
32    public synchronized void transfer(int from, int to, double amount) throws InterruptedException
33    {
34       while (accounts[from] < amount)
35          wait();//来自Object类
36       System.out.print(Thread.currentThread());
37       accounts[from] -= amount;
38       System.out.printf(" %10.2f from %d to %d", amount, from, to);
39       accounts[to] += amount;
40       System.out.printf(" Total Balance: %10.2f%n", getTotalBalance());
41       notifyAll();//解除所有线程的阻塞状态
42    }
43 
44    /**
45     * Gets the sum of all account balances.
46     * @return the total balance
47     */
48    public synchronized double getTotalBalance()
49    {
50       double sum = 0;
51 
52       for (double a : accounts)
53          sum += a;
54 
55       return sum;
56    }
57 
58    /**
59     * Gets the number of accounts in the bank.
60     * @return the number of accounts
61     */
62    public int size()
63    {
64       return accounts.length;
65    }
66 }
Bank

 

 1 package synch2;
 2 
 3 /**
 4  * This program shows how multiple threads can safely access a data structure,
 5  * using synchronized methods.
 6  * @version 1.31 2015-06-21
 7  * @author Cay Horstmann
 8  */
 9 public class SynchBankTest2
10 {
11    public static final int NACCOUNTS = 100;
12    public static final double INITIAL_BALANCE = 1000;
13    public static final double MAX_AMOUNT = 1000;
14    public static final int DELAY = 10;
15 
16    public static void main(String[] args)
17    {
18       Bank bank = new Bank(NACCOUNTS, INITIAL_BALANCE);
19       for (int i = 0; i < NACCOUNTS; i++)
20       {
21          int fromAccount = i;
22          Runnable r = () -> {
23             try
24             {
25                while (true)
26                {
27                   int toAccount = (int) (bank.size() * Math.random());
28                   double amount = MAX_AMOUNT * Math.random();
29                   bank.transfer(fromAccount, toAccount, amount);
30                   Thread.sleep((int) (DELAY * Math.random()));
31                }
32             }
33             catch (InterruptedException e)
34             {
35             }
36          };
37          Thread t = new Thread(r);
38          t.start();
39       }
40    }
41 }
SynchBankTest2

测试程序3:

l 在Elipse环境下运行以下程序,结合程序运行结果分析程序存在问题;

l 尝试解决程序中存在问题。

class Cbank

{

     private static int s=2000;

     public   static void sub(int m)

     {

           int temp=s;

           temp=temp-m;

          try {

      Thread.sleep((int)(1000*Math.random()));

    }

           catch (InterruptedException e)  {              }

           s=temp;

           System.out.println("s="+s);

   }

}

 

 

class Customer extends Thread

{

  public void run()

  {

   for( int i=1; i<=4; i++)

     Cbank.sub(100);

    }

 }

public class Thread3

{

 public static void main(String args[])

  {

   Customer customer1 = new Customer();

   Customer customer2 = new Customer();

   customer1.start();

   customer2.start();

  }

}

 1 class Cbank
 2 {
 3      private static int s=2000;
 4      public   static synchronized void sub(int m)
 5      {
 6 
 7            int temp=s;
 8            temp=temp-m;
 9           try {
10                  Thread.sleep((int)(1000*Math.random()));
11                }
12            catch (InterruptedException e)  {              }
13               s=temp;
14               System.out.println("s="+s);
15           }
16     }
17 
18 
19 class Customer extends Thread
20 {
21   public void run()
22   {
23    for( int i=1; i<=4; i++)
24      Cbank.sub(100);
25     }
26  }
27 public class Thread3
28 {
29  public static void main(String args[])
30   {
31    Customer customer1 = new Customer();
32    Customer customer2 = new Customer();
33    customer1.start();
34    customer2.start();
35   }
36 }
Cbank

实验2 编程练习

利用多线程及同步方法,编写一个程序模拟火车票售票系统,共3个窗口,卖10张票,程序输出结果类似(程序输出不唯一,可以是其他类似结果)。

Thread-0窗口售:第1张票

Thread-0窗口售:第2张票

Thread-1窗口售:第3张票

Thread-2窗口售:第4张票

Thread-2窗口售:第5张票

Thread-1窗口售:第6张票

Thread-0窗口售:第7张票

Thread-2窗口售:第8张票

Thread-1窗口售:第9张票

Thread-0窗口售:第10张票

 1 public class Demo {
 2     public static void main(String[] args) {
 3         Myrhread myrhread = new Myrhread();
 4         Thread t1 = new Thread(myrhread);
 5         Thread t2 = new Thread(myrhread);
 6         Thread t3 = new Thread(myrhread);
 7         t1.start();
 8         t2.start();
 9         t3.start();
10     }
11 }
12 
13 class Myrhread implements Runnable {
14     int t = 1;
15     boolean flag = true;
16 
17     public void run() {
18         while (flag) {
19             try {
20                 Thread.sleep(500);
21             } catch (InterruptedException e) {
22                 e.printStackTrace();
23             }
24             synchronized (this) {
25                 if (t <= 10) {
26                     System.out.println(Thread.currentThread().getName() + "窗口售:第" + t + "張票");
27                     t++;
28                 }
29                 if (t > 10) {
30                     flag = false;
31                 }
32             }
33         }
34 
35     }
36 }
Demo

3.实验总结:

本周的实验容量很少,实验也相对来说简单,完成的还算顺利。学长也教了我们常用的一些快捷键,本周的收获还是很大的。

 

posted @ 2018-12-23 13:23  薄荷蓝莓  阅读(152)  评论(0编辑  收藏  举报