Regular Expression Matching
2014-12-15 17:06 李涛的技术博客 阅读(132) 评论(0) 编辑 收藏 举报Implement regular expression matching with support for '.' and '*'.
'.' Matches any single character.
'*' Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char* s, const char* p)
Some examples:
isMatch("aa", "a") --> false
isMatch("aa", "aa") --> true
isMatch("aaa", "aa") --> false
isMatch("aa", "a*") --> true
isMatch("aa", ".*") --> true
isMatch("ab", ".*") --> true
isMatch("aab", "c*a*b") --> true
bool isMatch(const char* s, const char* p) { if (s == NULL || p == NULL) return false; if (*p == '\0') return *s == '\0'; // next char is not '*' if (*(p+1) != '*') return ((*p == *s) || (*p == '.' && *s != '\0')) && isMatch(s+1, p+1); // next char is '*' while ((*p == *s) || (*p == '.' && *s != '\0')) { if (isMatch(s, p+2)) return true; s++; } return isMatch(s, p+2); }
http://leetcode.com/2011/09/regular-expression-matching.html