摘要：
第一题#include#includeint main(){double x1,x2,m;int a,b,c;scanf("%d%d%d",&a,&b,&c);while(1){if(a==b&&b==c&&c==0)break;m=1.0*b*b-4*a*c;if(a==0)printf("Error!\n"); if((a!=0)&&(m0){x1=(-b+sqrt(m))/(2*a);x2=(-b-sqrt(m))/(2*a);printf("x1=%lf\n&quo 阅读全文
