LeetCode-Range Addition

Assume you have an array of length n initialized with all 0's and are given k update operations.

Each operation is represented as a triplet: [startIndex, endIndex, inc] which increments each element of subarray A[startIndex ... endIndex] (startIndex and endIndex inclusive) with inc.

Return the modified array after all k operations were executed.

Example:

Given:

    length = 5,
    updates = [
        [1,  3,  2],
        [2,  4,  3],
        [0,  2, -2]
    ]

Output:

    [-2, 0, 3, 5, 3]

Explanation:

Initial state:
[ 0, 0, 0, 0, 0 ]

After applying operation [1, 3, 2]:
[ 0, 2, 2, 2, 0 ]

After applying operation [2, 4, 3]:
[ 0, 2, 5, 5, 3 ]

After applying operation [0, 2, -2]:
[-2, 0, 3, 5, 3 ]

Solution:

 1 public class Solution {
 2     public int[] getModifiedArray(int length, int[][] updates) {
 3         int[] res = new int[length];
 4         Arrays.fill(res,0);
 5         for (int[] update : updates){
 6             int start = update[0];
 7             int end = update[1]+1;
 8             int val = update[2];
 9 
10             res[start] += val;
11             if (end<length){
12                 res[end] -= val;
13             }
14         }
15 
16         int sum = 0;
17         for (int i=0;i<length;i++){
18             sum += res[i];
19             res[i] = sum;
20         }
21         return res;
22     }
23 }

 

posted @ 2016-07-21 14:35  LiBlog  阅读(115)  评论(0编辑  收藏  举报