LintCode-Rotate String

Given a string and an offset, rotate string by offset. (rotate from left to right)

Example

Given "abcdefg"

for offset=0, return "abcdefg"

for offset=1, return "gabcdef"

for offset=2, return "fgabcde"

for offset=3, return "efgabcd"

Solution:

 1 public class Solution {
 2     /*
 3      * param A: A string
 4      * param offset: Rotate string with offset.
 5      * return: Rotated string.
 6      */
 7     public char[] rotateString(char[] A, int offset) {
 8         if (A.length==0) return A;
 9         offset = offset % A.length;
10         if (offset == 0) return A;
11         int len = A.length;
12         //Store the rotated char in buffer.
13         char[] buff = new char[offset];
14         for (int i=len-offset;i<len;i++)
15             buff[i-len+offset] = A[i];
16 
17         //Move the left chars to right.
18         for (int i=len-offset-1;i>=0;i--)
19             A[i+offset] = A[i];
20 
21         //Put the chars in buff into array.
22         for (int i=0;i<offset;i++)
23             A[i] = buff[i];
24 
25         return A;
26     }
27 };

 

posted @ 2014-12-25 09:52  LiBlog  阅读(346)  评论(0)  编辑  收藏  举报