摘要: #include#includeint main(void){ int n,i,sum; printf("Enter n:"); scanf("%d",&n); sum=0; for(i=1;i<=n;i++){ sum=pow(2,i); } printf("sum=%.d\n",sum); return 0;} 阅读全文
posted @ 2013-10-19 23:04 liruijia 阅读(98) 评论(0) 推荐(0) 编辑
摘要: #include #include int main(void) { int year; double loan,money,my,rate; scanf("%Lf",&loan); scanf("%Lf",&rate); printf("year money\n"); for(year=5;year<=30;year++){ my=pow(1+rate,12*year); money=loan*rate*my/(my-1); printf("year=%d money=%.0f\n",yea 阅读全文
posted @ 2013-10-19 23:03 liruijia 阅读(89) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int denominator,n,i; double sum,m; printf("Enter n:"); scanf("%d",&n); sum=0; denominator=1; for(i=m;i<=n;i++){ sum=sum+i*i+1.0/denominator; denominator=denominator+1; } printf("sum=%.2f\n",sum); return 0;} 阅读全文
posted @ 2013-10-19 22:59 liruijia 阅读(92) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int denominator,i,n; double item,sum,flag; flag=1; denominator=1; sum=0; printf("Enter n:"); scanf("%d",&n); for(i=1;i<=n;i++){ item=(flag*i)/denominator; sum=sum+item; flag=-flag; denominator=denominator+2; } printf("... 阅读全文
posted @ 2013-10-19 22:58 liruijia 阅读(93) 评论(0) 推荐(0) 编辑
摘要: #include int main() { double x,pow = 1.0; int i,n; printf("Enter x:"); scanf("%lf",&x);printf("Enter n:");scanf("%d",&n); for(i=1;i<=n;i++){pow=pow*x;}printf("pow(%lf%d)=%.2f\n",x,n,pow);return 0;} 阅读全文
posted @ 2013-10-19 22:57 liruijia 阅读(64) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int num1,num2,a,b,c; double d,e; printf("输入num1,num2:"); scanf("%d%d",&num1,&num2); a=num1+num2; b=num1-num2; c=num1*num2; d=num1/num2; e=num1%num2; printf("输出和=%d差=%d积=%d商=%.2f余数=%.2f",a,b,c,d,e); return 0;} 阅读全文
posted @ 2013-10-19 22:36 liruijia 阅读(62) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,n; double x,y; double fee(double x); printf("Enter n:"); scanf("%d",&n); for(i=1;i<=n;i++) { printf("Enter x:"); scanf("%Lf",&x); if(x<=0) printf("输入错误,重新输入"); else{ y=fee(x); } printf(... 阅读全文
posted @ 2013-10-19 21:57 liruijia 阅读(86) 评论(0) 推荐(0) 编辑
摘要: #includeint main(){ int n,i; double x,y; printf("Enter n:"); scanf("%d",&n); for(i=1;i<=n;i++){ printf("Enter x:"); scanf("%lf",&x); if(x<=0) printf("输入错误,请重新输入\n"); else if(x<=50){ y=0.53*x; } else{ y=26.5+0... 阅读全文
posted @ 2013-10-19 21:46 liruijia 阅读(102) 评论(0) 推荐(0) 编辑