Codeforces Round #628 (Div. 2) B. CopyCopyCopyCopyCopy(水题)
Ehab has an array aa of length nn . He has just enough free time to make a new array consisting of nn copies of the old array, written back-to-back. What will be the length of the new array's longest increasing subsequence?
A sequence aa is a subsequence of an array bb if aa can be obtained from bb by deletion of several (possibly, zero or all) elements. The longest increasing subsequence of an array is the longest subsequence such that its elements are ordered in strictly increasing order.
The first line contains an integer tt — the number of test cases you need to solve. The description of the test cases follows.
The first line of each test case contains an integer nn (1≤n≤1051≤n≤105 ) — the number of elements in the array aa .
The second line contains nn space-separated integers a1a1 , a2a2 , …… , anan (1≤ai≤1091≤ai≤109 ) — the elements of the array aa .
The sum of nn across the test cases doesn't exceed 105105 .
For each testcase, output the length of the longest increasing subsequence of aa if you concatenate it to itself nn times.
2 3 3 2 1 6 3 1 4 1 5 9
3 5
求这个序列里有多少个不重复的元素即可(因为能复制无数遍)。]
#include <bits/stdc++.h> using namespace std; int main() { int t; cin>>t; while(t--) { int n; set<int>s; int i; cin>>n; for(i=1;i<=n;i++) { int temp; scanf("%d",&temp); s.insert(temp); } cout<<s.size()<<endl; } return 0; }
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