练习案例_甩不掉的跟屁虫

 

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
    <meta http-equiv="Content-Type" content="text/html;charset=utf-8">
    <title>甩不掉的跟屁虫</title>
    <script type="text/javascript" src="jquery-1.8.3.js"></script>
    <script type="text/javascript">
        $(document).ready(function(){

            $("#bug").css("position","absolute");

            $(document).mousemove(function () {
                var mouseX = event.clientX;
                var mouseY = event.clientY;

                $("#bug").css("top",mouseY+"px");
                $("#bug").css("left",mouseX-$("#bug").prop("offsetWidth")+"px");
            });

        });
    </script>
</head>
<body>
    <img id="bug" src="image/跟屁虫.png" alt="跟屁虫" />
</body>
</html>

 

 

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
    <meta http-equiv="Content-Type" content="text/html;charset=utf-8">
    <title></title>
    <script type="text/javascript">

        window.onload=function(){

            var imgBug = document.getElementById("imgBug");

            imgBug.style.position = "absolute";

            //1 注册鼠标移动的事件处理函数
            document.onmousemove=function(){

                //2 改变图片的坐标
                //获取鼠标的坐标
                var x = event.clientX;
                var y = event.clientY;


                imgBug.style.left = x - imgBug.offsetWidth +"px";

                imgBug.style.top = y+"px";

            }


        }

    </script>
</head>
<body>
<img id="imgBug" src="image/跟屁虫.png" alt="跟屁虫"/>
</body>
</html>

 

posted @ 2016-06-09 17:25  linyongqin  阅读(203)  评论(0)  编辑  收藏  举报