LeetCode-95 Unique Binary Search Trees II

Given n, generate all structurally unique BST's (binary search trees) that store values 1...n.

For example,
Given n = 3, your program should return all 5 unique BST's shown below.

   1         3     3      2      1
    \       /     /      / \      \
     3     2     1      1   3      2
    /     /       \                 \
   2     1         2                 3


代码如下:
public List<TreeNode> generateTrees(int n) {
        if(n < 1) {
            List<TreeNode> list = new ArrayList<TreeNode>();
            list.add(null);
            return list;
        }
        return generateTree(1, n);
    }
    
    public List<TreeNode> generateTree(int start ,int over) {
        List<TreeNode> list = new ArrayList<TreeNode>();
        if(start > over) {
            list.add(null);
            return list;
        }
        if(start == over) {
            list.add(new TreeNode(start));
            return list;
        }
        
        for(int i=start; i<=over; i++) {
            List<TreeNode> leftList = generateTree(start ,i-1);
            List<TreeNode> rightList = generateTree(i+1 ,over);
            for(TreeNode left : leftList) {
                for(TreeNode right : rightList) {
                    TreeNode root = new TreeNode(i);
                    root.left = left;
                    root.right = right;
                    list.add(root);
                }
            }
        }
        return list;
    }

 

posted on 2015-03-11 22:23  linxiong1991  阅读(100)  评论(0编辑  收藏  举报

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