摘要: 1. 显⽰uid⼤于等于500,输出common user,⽤户名和uid,否则输出sysuser awk F: '{$3 =500?usertype="common user":usertype="sysuser";printf "% 15s % 20s %10d\n",usertype,$1,$ 阅读全文
posted @ 2019-06-23 21:17 Linux老司机 阅读(205) 评论(0) 推荐(0) 编辑