python Django中的加密解密

dboptplat 运维工具中的加密解密


[root@localhost dboptplatAA]# python2.7 manage.py shell
Python 2.7.12 (default, Sep 28 2016, 16:34:21)
[GCC 4.4.7 20120313 (Red Hat 4.4.7-16)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
(InteractiveConsole)
>>> from common import mycrypt
>>> from dboptplat import myconfig
>>> cry = mycrypt.mycrypt(myconfig.ck)
>>> from Crypto.Cipher import AES
>>> cry.encrypt("hellio");
'b9650281cbe0a75a39878bfba9e305a3'

>>> cry.decrypt("b9650281cbe0a75a39878bfba9e305a3");
'hellio'

 

============================Django 完整加密解密===============================

#coding:utf8
import sys
from Crypto.Cipher import AES
from binascii import b2a_hex, a2b_hex
 
class prpcrypt():
    def __init__(self, key):
        self.key = key
        self.mode = AES.MODE_CBC
     
    #加密函数，如果text不是16的倍数【加密文本text必须为16的倍数！】，那就补足为16的倍数
    def encrypt(self, text):
        cryptor = AES.new(self.key, self.mode, self.key)
        #这里密钥key 长度必须为16（AES-128）、24（AES-192）、或32（AES-256）Bytes 长度.目前AES-128足够用
        length = 16
        count = len(text)
        add = length - (count % length)
        text = text + ('\0' * add)
        self.ciphertext = cryptor.encrypt(text)
        #因为AES加密时候得到的字符串不一定是ascii字符集的，输出到终端或者保存时候可能存在问题
        #所以这里统一把加密后的字符串转化为16进制字符串
        return b2a_hex(self.ciphertext)
     
    #解密后，去掉补足的空格用strip() 去掉
    def decrypt(self, text):
        cryptor = AES.new(self.key, self.mode, self.key)
        plain_text = cryptor.decrypt(a2b_hex(text))
        return plain_text.rstrip('\0')
 
if __name__ == '__main__':
    pc = prpcrypt("Js%iR>'h.B3:Hpwq")      #初始化密钥
    a = pc.encrypt("linqiuhua_test")
    a1 = pc.decrypt(a)                     
    b = pc.decrypt('f947679015454c6bcedaff555bd6cc0a')
    d = pc.decrypt('824e3a2a5a5824eb63ecc46e9fba9332')
    e = pc.decrypt('7c523d21f61a61b9a1eb85b183e49567')
    #d = pc.decrypt(e)
    #print "=================================="                 
    print a
    print a1
   # print b
   # print d
   # print e