摘要: SELECT substring_index(substring_index(a.chain,'_',b.help_topic_id + 1),'_' ,- 1)AS ID FROM (select '1_11_1223_1242' as chain) a JOIN mysql.help_topic 阅读全文
posted @ 2023-04-18 14:25 寒冷的雨呢 阅读(313) 评论(0) 推荐(0) 编辑