springboot-jpa获取session

springboot获取hibernate的session进行更精细的SQL操作,默认的jpa并不能满足一些复杂需求(可能是我把需求设计复杂了)
通过查看JpaRepository的底层实现,发现是通过EntityManager进行数据库会话操作,因此进一步获取它管理的会话。

    @Autowired
    private UserDao userDao;
    @Autowired
    private EntityManager entityManager;


    @Transactional// 涉及更新删除,需要开启事务
    @Override
    public void run(ApplicationArguments args) throws Exception {
        // 获取会话,,,使用 unwrap 返回 EntityManager 的底层实现
        Session session = entityManager.unwrap(Session.class);

        User byUsername = userDao.findByUsername("123");
        if (byUsername == null) {
            User user = new User();
            user.setUsername("123");
            user.setPassword("123");
            user.setNickname("管理员");
            session.save(user);
            // springboot 2.3.12 使用的是 hibernate 5.4.x
            List username = session.createQuery("from User u where username=:username")
                    .setParameter("username", "123").list();
            System.out.println(username);

            Role role = new Role();
            role.setName("admin");
            session.save(role);

            UserToRole userToRole = new UserToRole();
            userToRole.setUser(user);
            userToRole.setRole(role);
            session.save(userToRole);

            Authority authority = new Authority();
            authority.setUrl("/**");
            session.save(authority);

            Menu menu = new Menu();
            menu.setUrl("/index");
            menu.setSeq(0);
            menu.setTitle("主页");
            session.save(menu);

            session.save(new RoleToAuthority(role, authority));
            session.save(new RoleToMenu(role, menu));
        }
        // 此处要注意 使用User的细节
        List username = session.createQuery("from User u where username=:username")
                .setParameter("username", "123").list();
        System.out.println(username);
    }

我们注意到上面使用User的细节,不是使用表名ad_user,而是直接使用实体User,

@Entity
@Table(name = "ad_user") // import javax.persistence.Table
@org.hibernate.annotations.Table(appliesTo = "ad_user", comment = "用户表")
@Data
public class User

// 对应  User
List username = session.createQuery("from User u where username=:username")
        .setParameter("username", "123").list();
@Entity(name = "ad_user")
//@Table(name = "ad_user") // import javax.persistence.Table
@org.hibernate.annotations.Table(appliesTo = "ad_user", comment = "用户表")
@Data
public class User

// 对应  ad_user 
List username = session.createQuery("from ad_user u where username=:username")
                .setParameter("username", "123").list();

建议使用第一种!

posted @ 2022-09-16 00:08  凌康  阅读(441)  评论(0编辑  收藏  举报