PAT (Advanced Level) Practice 1058 A+B in Hogwarts (20 分) 凌宸1642

PAT (Advanced Level) Practice 1058 A+B in Hogwarts (20 分) 凌宸1642

题目描述：

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

译：如果你是哈利·波特的粉丝，你就会知道魔法世界有自己的货币体系——正如海格对哈利解释的那样:“17个银西可兑换1个加隆，29个纳特兑换1个银西，很简单。”你的工作是写一个程序来计算 A +B 其中 A 和 B 是以标准形式给出的 Galleon.Sickle.Knut (Galleon是[0,10⁷]中的整数，Sickle 是[0 , 17) 中的整数，Knut 是[ 0 , 29)))。

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Input Specification (输入说明):

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

译：每个测试文件包含一个测试用例，在一行中A 和 B 按标准的形式输入，并用空格分隔。

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Output Specification (输出说明):

For each test case you should output the sum of A and B in one line, with the same format as the input.

译：对于每个测试用例，你应该按输入的格式输出 A + B 的和 。

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Sample Input (样例输入):

3.2.1 10.16.27

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Sample Output (样例输出):

14.1.28

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The Idea：

很简单！！就是从 Knut 开始相加，如果 Kunt 大于等于 29 则需要进位给 Sickle ，然后 Sickle 相加，有进位需要进位给 Galleon 然后再按格式输出即可。

The Codes:

#include<bits/stdc++.h>
using namespace std;
int g1 , s1, k1 , g2 , s2, k2 , g3 , s3, k3 ;
int main(){
	scanf("%d.%d.%d %d.%d.%d" , &g1 , &s1 , &k1 , &g2 , &s2, &k2);
	k3 = (k1 + k2) % 29 ;
	s3 = (s1 + s2 + (k1 + k2) / 29) % 17 ;
	g3 = g1 + g2 + (s1 + s2 + (k1 + k2) / 29) / 17 ;
	printf("%d.%d.%d\n" , g3 , s3 , k3) ;
	return 0;
}