Python练习四

1.任意输入一串文字加数字,统计出数字的个数,数字相连的视为一个,如:12fd2表示两个数字,即12为一个数字。

content = input("请输入内容:")
for i in content:
    if i.isalpha():
        content = content.replace(i, " ")
s = content.split()
print(len(s))

  2.有如下值li= [11,22,33,44,55,66,77,88,99,90],将所有大于 66 的值保存至字典的第一个key中,将小于 66 的值保存至第二个key的值中。即: {'k1': 大于66的所有值列表, 'k2': 小于66的所有值列表}

li = [11, 22, 33, 44, 55, 66, 77, 88, 99, 90]
dic = {"k1": [], "k2": []}
for i in li:
if i > 66:
dic["k1"].append(i)
elif i == 66:
continue
else:
dic["k2"].append(i)
print(dic)

 3.输出商品列表,用户输入序号,显示用户选中的商品.li = ["手机", "电脑", '鼠标垫', '游艇']

要求:1:页面显示 序号 + 商品名称,如:

1 手机
2 电脑
2: 用户输入选择的商品序号,然后打印商品名称
3:如果用户输入的商品序号有误,则提示输入有误,并重新输入。
4:用户输入Q或者q,退出程序。

while 1:
    li = ["手机", "电脑", '鼠标垫', '游艇']
    for i in li:
        print(li.index(i) + 1, i)
    content = input("请输入商品序号:")
    if content.isdigit():
        content = int(content)
        if content > 0 and content <= len(li):
            print(li[content - 1])
        else:
            print("请输入有效数字")
    elif content.upper() == "Q":
        print("退出程序")
        break
    else:
        print("输入有误,请重新输入:")

 4.购物车

li = [
    {"name": "苹果", "price": 10},
    {"name": "西瓜", "price": 31},
    {"name": "菠萝", "price": 24},
    {"name": "香蕉", "price": 20}
]
shopping_car = {}
print("欢迎光临小赖水果店")
money = input("让我看看你的钱:")
while 1:
    for i, k in enumerate(li):
        print("序号{},商品{},价格{}".format(i, k["name"], k["price"]))
    choose = input("请输入要购买商品的序号:")
    if choose.isdigit() and int(choose) <= int(len(li)):
        num = input("请输入要购买的数量:")
        if num.isdigit():
            if int(money) >= li[int(choose)]["price"] * int(num):
                money = int(money) - li[int(choose)]["price"] * int(num)
                if li[int(choose)]["name"] in shopping_car:
                    shopping_car[li[int(choose)]["name"]] = shopping_car[li[int(choose)]["name"]] + int(num)
                else:
                    shopping_car[li[int(choose)]["name"]] = int(num)
                print("购物车中的商品有{},您的余额还有{}".format(shopping_car, money))
            else:
                print("穷鬼,回去找你老婆要钱去吧")
        else:
            print("您输入有误")
    else:
        print("请你输入正确的序号")
        continue

5.删除字典中键值对中的键含有k的元素。dic = {"k1":"aa", "kf":"cc", "aw":"gg", "3k":"dd"}。

# 方法一:
dic = {"k1": "aa", "kf": "cc", "aw": "gg", "3k": "dd"}
dic2 = {}
for i in dic:
    if "k" not in i:
        dic2.setdefault(i, dic[i])
dic = dic2
print(dic)

# 方法二:
dic = {"k1": "aa", "kf": "cc", "aw": "gg", "3k": "dd"}
li = []
for i in dic:
    if "k" in i:
        li.append(i)
for i in li:
    del dic[i]
print(dic)

 

posted @ 2019-01-30 11:24  彬彬有礼丶林  阅读(280)  评论(0编辑  收藏  举报