百度坐标(BD09)、国测局坐标(火星坐标,GCJ02)、和WGS84坐标系之间的转换(JS版代码)

转载自:http://www.cnblogs.com/lycnblogs/archive/2015/10/16/4885536.html
/**
 * Created by Wandergis on 2015/7/8.
 * 提供了百度坐标(BD09)、国测局坐标(火星坐标,GCJ02)、和WGS84坐标系之间的转换
 */
 
//定义一些常量
var x_PI = 3.14159265358979324 * 3000.0 / 180.0;
var PI = 3.1415926535897932384626;
var a = 6378245.0;
var ee = 0.00669342162296594323;
 
/**
 * 百度坐标系 (BD-09) 与 火星坐标系 (GCJ-02)的转换
 * 即 百度 转 谷歌、高德
 * @param bd_lon
 * @param bd_lat
 * @returns {*[]}
 */
function bd09togcj02(bd_lon, bd_lat) {
    var x_pi = 3.14159265358979324 * 3000.0 / 180.0;
    var x = bd_lon - 0.0065;
    var y = bd_lat - 0.006;
    var z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);
    var theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);
    var gg_lng = z * Math.cos(theta);
    var gg_lat = z * Math.sin(theta);
    return [gg_lng, gg_lat]
}
 
/**
 * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换
 * 即谷歌、高德 转 百度
 * @param lng
 * @param lat
 * @returns {*[]}
 */
function gcj02tobd09(lng, lat) {
    var z = Math.sqrt(lng * lng + lat * lat) + 0.00002 * Math.sin(lat * x_PI);
    var theta = Math.atan2(lat, lng) + 0.000003 * Math.cos(lng * x_PI);
    var bd_lng = z * Math.cos(theta) + 0.0065;
    var bd_lat = z * Math.sin(theta) + 0.006;
    return [bd_lng, bd_lat]
}
 
/**
 * WGS84转GCj02
 * @param lng
 * @param lat
 * @returns {*[]}
 */
function wgs84togcj02(lng, lat) {
    if (out_of_china(lng, lat)) {
        return [lng, lat]
    }
    else {
        var dlat = transformlat(lng - 105.0, lat - 35.0);
        var dlng = transformlng(lng - 105.0, lat - 35.0);
        var radlat = lat / 180.0 * PI;
        var magic = Math.sin(radlat);
        magic = 1 - ee * magic * magic;
        var sqrtmagic = Math.sqrt(magic);
        dlat = (dlat * 180.0) / ((a * (1 - ee)) / (magic * sqrtmagic) * PI);
        dlng = (dlng * 180.0) / (a / sqrtmagic * Math.cos(radlat) * PI);
        var mglat = lat + dlat;
        var mglng = lng + dlng;
        return [mglng, mglat]
    }
}
 
/**
 * GCJ02 转换为 WGS84
 * @param lng
 * @param lat
 * @returns {*[]}
 */
function gcj02towgs84(lng, lat) {
    if (out_of_china(lng, lat)) {
        return [lng, lat]
    }
    else {
        var dlat = transformlat(lng - 105.0, lat - 35.0);
        var dlng = transformlng(lng - 105.0, lat - 35.0);
        var radlat = lat / 180.0 * PI;
        var magic = Math.sin(radlat);
        magic = 1 - ee * magic * magic;
        var sqrtmagic = Math.sqrt(magic);
        dlat = (dlat * 180.0) / ((a * (1 - ee)) / (magic * sqrtmagic) * PI);
        dlng = (dlng * 180.0) / (a / sqrtmagic * Math.cos(radlat) * PI);
        mglat = lat + dlat;
        mglng = lng + dlng;
        return [lng * 2 - mglng, lat * 2 - mglat]
    }
}
 
function transformlat(lng, lat) {
    var ret = -100.0 + 2.0 * lng + 3.0 * lat + 0.2 * lat * lat + 0.1 * lng * lat + 0.2 * Math.sqrt(Math.abs(lng));
    ret += (20.0 * Math.sin(6.0 * lng * PI) + 20.0 * Math.sin(2.0 * lng * PI)) * 2.0 / 3.0;
    ret += (20.0 * Math.sin(lat * PI) + 40.0 * Math.sin(lat / 3.0 * PI)) * 2.0 / 3.0;
    ret += (160.0 * Math.sin(lat / 12.0 * PI) + 320 * Math.sin(lat * PI / 30.0)) * 2.0 / 3.0;
    return ret
}
 
function transformlng(lng, lat) {
    var ret = 300.0 + lng + 2.0 * lat + 0.1 * lng * lng + 0.1 * lng * lat + 0.1 * Math.sqrt(Math.abs(lng));
    ret += (20.0 * Math.sin(6.0 * lng * PI) + 20.0 * Math.sin(2.0 * lng * PI)) * 2.0 / 3.0;
    ret += (20.0 * Math.sin(lng * PI) + 40.0 * Math.sin(lng / 3.0 * PI)) * 2.0 / 3.0;
    ret += (150.0 * Math.sin(lng / 12.0 * PI) + 300.0 * Math.sin(lng / 30.0 * PI)) * 2.0 / 3.0;
    return ret
}
 
/**
 * 判断是否在国内,不在国内则不做偏移
 * @param lng
 * @param lat
 * @returns {boolean}
 */
function out_of_china(lng, lat) {
    return (lng < 72.004 || lng > 137.8347) || ((lat < 0.8293 || lat > 55.8271) || false);
}

 还有另一个算法,来自这里,经测试,算法结果是一样的。

https://github.com/hiwanz/wgs2mars.js/

----------------------- 华丽的分割线 ------------------------

C语言版本,来自

https://github.com/Dronaldo17/ChinaMapShift/blob/master/algorithm/china_shift.c

//
//  china_shift.c
//
//  Most code created by someone anonymous. Thank you, someone.
//  transformFromGCJToWGS() added by Fengzee (fengzee@fengzee.com).
//

#include "china_shift.h"
#include <math.h>

Location LocationMake(double lng, double lat) {
    Location loc; loc.lng = lng, loc.lat = lat; return loc;
}

///
///  Transform WGS-84 to GCJ-02 (Chinese encrypted coordination system)
///

const double pi = 3.14159265358979324;

//
// Krasovsky 1940
//
// a = 6378245.0, 1/f = 298.3
// b = a * (1 - f)
// ee = (a^2 - b^2) / a^2;
const double a = 6378245.0;
const double ee = 0.00669342162296594323;

int outOfChina(double lat, double lon)
{
    if (lon < 72.004 || lon > 137.8347)
        return 1;
    if (lat < 0.8293 || lat > 55.8271)
        return 1;
    return 0;
}

double transformLat(double x, double y)
{
    double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * sqrt(x > 0 ? x:-x);
    ret += (20.0 * sin(6.0 * x * pi) + 20.0 *sin(2.0 * x * pi)) * 2.0 / 3.0;
    ret += (20.0 * sin(y * pi) + 40.0 * sin(y / 3.0 * pi)) * 2.0 / 3.0;
    ret += (160.0 * sin(y / 12.0 * pi) + 320 * sin(y * pi / 30.0)) * 2.0 / 3.0;
    return ret;
}

double transformLon(double x, double y)
{
    double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(x > 0 ? x:-x);
    ret += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0;
    ret += (20.0 * sin(x * pi) + 40.0 * sin(x / 3.0 * pi)) * 2.0 / 3.0;
    ret += (150.0 * sin(x / 12.0 * pi) + 300.0 * sin(x / 30.0 * pi)) * 2.0 / 3.0;
    return ret;
}

Location transformFromWGSToGCJ(Location wgLoc)
{
    Location mgLoc;
    if (outOfChina(wgLoc.lat, wgLoc.lng))
    {
        mgLoc = wgLoc;
        return mgLoc;
    }
    double dLat = transformLat(wgLoc.lng - 105.0, wgLoc.lat - 35.0);
    double dLon = transformLon(wgLoc.lng - 105.0, wgLoc.lat - 35.0);
    double radLat = wgLoc.lat / 180.0 * pi;
    double magic = sin(radLat);
    magic = 1 - ee * magic * magic;
    double sqrtMagic = sqrt(magic);
    dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
    dLon = (dLon * 180.0) / (a / sqrtMagic * cos(radLat) * pi);
    mgLoc.lat = wgLoc.lat + dLat;
    mgLoc.lng = wgLoc.lng + dLon;
    
    return mgLoc;
}

///
///  Transform GCJ-02 to WGS-84
///  Reverse of transformFromWGSToGC() by iteration.
///
///  Created by Fengzee (fengzee@fengzee.me).
///
Location transformFromGCJToWGS(Location gcLoc)
{
    Location wgLoc = gcLoc;
    Location currGcLoc, dLoc;
    while (1) {
        currGcLoc = transformFromWGSToGCJ(wgLoc);
        dLoc.lat = gcLoc.lat - currGcLoc.lat;
        dLoc.lng = gcLoc.lng - currGcLoc.lng;
        if (fabs(dLoc.lat) < 1e-7 && fabs(dLoc.lng) < 1e-7) {  // 1e-7 ~ centimeter level accuracy
          // Result of experiment:
          //   Most of the time 2 iterations would be enough for an 1e-8 accuracy (milimeter level).
          //
            return wgLoc;
        }
        wgLoc.lat += dLoc.lat;
        wgLoc.lng += dLoc.lng;
    }
    
    return wgLoc;
}

///
///  Transform GCJ-02 to BD-09
///
const double x_pi = 3.14159265358979324 * 3000.0 / 180.0;
Location bd_encrypt(Location gcLoc)
{
    double x = gcLoc.lng, y = gcLoc.lat;
    double z = sqrt(x * x + y * y) + 0.00002 * sin(y * x_pi);
    double theta = atan2(y, x) + 0.000003 * cos(x * x_pi);
    return LocationMake(z * cos(theta) + 0.0065, z * sin(theta) + 0.006);
}

///
///  Transform BD-09 to GCJ-02
///
Location bd_decrypt(Location bdLoc)
{
    double x = bdLoc.lng - 0.0065, y = bdLoc.lat - 0.006;
    double z = sqrt(x * x + y * y) - 0.00002 * sin(y * x_pi);
    double theta = atan2(y, x) - 0.000003 * cos(x * x_pi);
    return LocationMake(z * cos(theta), z * sin(theta));
}

 

----------------------- 华丽的分割线 ------------------------

C#算法,来自 

https://on4wp7.codeplex.com/SourceControl/changeset/view/21483#353936

//
// Copyright (C) 1000 - 9999 Somebody Anonymous
// NO WARRANTY OR GUARANTEE
//

using System;

namespace Navi
{
    class EvilTransform
    {
        const double pi = 3.14159265358979324;

        //
        // Krasovsky 1940
        //
        // a = 6378245.0, 1/f = 298.3
        // b = a * (1 - f)
        // ee = (a^2 - b^2) / a^2;
        const double a = 6378245.0;
        const double ee = 0.00669342162296594323;

        //
        // World Geodetic System ==> Mars Geodetic System
        public static void transform(double wgLat, double wgLon, out double mgLat, out double mgLon)
        {
            if (outOfChina(wgLat, wgLon))
            {
                mgLat = wgLat;
                mgLon = wgLon;
                return;
            }
            double dLat = transformLat(wgLon - 105.0, wgLat - 35.0);
            double dLon = transformLon(wgLon - 105.0, wgLat - 35.0);
            double radLat = wgLat / 180.0 * pi;
            double magic = Math.Sin(radLat);
            magic = 1 - ee * magic * magic;
            double sqrtMagic = Math.Sqrt(magic);
            dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
            dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
            mgLat = wgLat + dLat;
            mgLon = wgLon + dLon;
        }

        static bool outOfChina(double lat, double lon)
        {
            if (lon < 72.004 || lon > 137.8347)
                return true;
            if (lat < 0.8293 || lat > 55.8271)
                return true;
            return false;
        }

        static double transformLat(double x, double y)
        {
            double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.Sqrt(Math.Abs(x));
            ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
            ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0;
            ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0;
            return ret;
        }

        static double transformLon(double x, double y)
        {
            double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.Sqrt(Math.Abs(x));
            ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
            ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0;
            ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0 * pi)) * 2.0 / 3.0;
            return ret;
        }
    }
}

 

posted on 2017-05-02 20:07  Lin557  阅读(4550)  评论(0编辑  收藏  举报

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