百度坐标(BD09)、国测局坐标(火星坐标,GCJ02)、和WGS84坐标系之间的转换(JS版代码)
转载自:http://www.cnblogs.com/lycnblogs/archive/2015/10/16/4885536.html
/** * Created by Wandergis on 2015/7/8. * 提供了百度坐标(BD09)、国测局坐标(火星坐标,GCJ02)、和WGS84坐标系之间的转换 */ //定义一些常量 var x_PI = 3.14159265358979324 * 3000.0 / 180.0; var PI = 3.1415926535897932384626; var a = 6378245.0; var ee = 0.00669342162296594323; /** * 百度坐标系 (BD-09) 与 火星坐标系 (GCJ-02)的转换 * 即 百度 转 谷歌、高德 * @param bd_lon * @param bd_lat * @returns {*[]} */ function bd09togcj02(bd_lon, bd_lat) { var x_pi = 3.14159265358979324 * 3000.0 / 180.0; var x = bd_lon - 0.0065; var y = bd_lat - 0.006; var z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi); var theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi); var gg_lng = z * Math.cos(theta); var gg_lat = z * Math.sin(theta); return [gg_lng, gg_lat] } /** * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换 * 即谷歌、高德 转 百度 * @param lng * @param lat * @returns {*[]} */ function gcj02tobd09(lng, lat) { var z = Math.sqrt(lng * lng + lat * lat) + 0.00002 * Math.sin(lat * x_PI); var theta = Math.atan2(lat, lng) + 0.000003 * Math.cos(lng * x_PI); var bd_lng = z * Math.cos(theta) + 0.0065; var bd_lat = z * Math.sin(theta) + 0.006; return [bd_lng, bd_lat] } /** * WGS84转GCj02 * @param lng * @param lat * @returns {*[]} */ function wgs84togcj02(lng, lat) { if (out_of_china(lng, lat)) { return [lng, lat] } else { var dlat = transformlat(lng - 105.0, lat - 35.0); var dlng = transformlng(lng - 105.0, lat - 35.0); var radlat = lat / 180.0 * PI; var magic = Math.sin(radlat); magic = 1 - ee * magic * magic; var sqrtmagic = Math.sqrt(magic); dlat = (dlat * 180.0) / ((a * (1 - ee)) / (magic * sqrtmagic) * PI); dlng = (dlng * 180.0) / (a / sqrtmagic * Math.cos(radlat) * PI); var mglat = lat + dlat; var mglng = lng + dlng; return [mglng, mglat] } } /** * GCJ02 转换为 WGS84 * @param lng * @param lat * @returns {*[]} */ function gcj02towgs84(lng, lat) { if (out_of_china(lng, lat)) { return [lng, lat] } else { var dlat = transformlat(lng - 105.0, lat - 35.0); var dlng = transformlng(lng - 105.0, lat - 35.0); var radlat = lat / 180.0 * PI; var magic = Math.sin(radlat); magic = 1 - ee * magic * magic; var sqrtmagic = Math.sqrt(magic); dlat = (dlat * 180.0) / ((a * (1 - ee)) / (magic * sqrtmagic) * PI); dlng = (dlng * 180.0) / (a / sqrtmagic * Math.cos(radlat) * PI); mglat = lat + dlat; mglng = lng + dlng; return [lng * 2 - mglng, lat * 2 - mglat] } } function transformlat(lng, lat) { var ret = -100.0 + 2.0 * lng + 3.0 * lat + 0.2 * lat * lat + 0.1 * lng * lat + 0.2 * Math.sqrt(Math.abs(lng)); ret += (20.0 * Math.sin(6.0 * lng * PI) + 20.0 * Math.sin(2.0 * lng * PI)) * 2.0 / 3.0; ret += (20.0 * Math.sin(lat * PI) + 40.0 * Math.sin(lat / 3.0 * PI)) * 2.0 / 3.0; ret += (160.0 * Math.sin(lat / 12.0 * PI) + 320 * Math.sin(lat * PI / 30.0)) * 2.0 / 3.0; return ret } function transformlng(lng, lat) { var ret = 300.0 + lng + 2.0 * lat + 0.1 * lng * lng + 0.1 * lng * lat + 0.1 * Math.sqrt(Math.abs(lng)); ret += (20.0 * Math.sin(6.0 * lng * PI) + 20.0 * Math.sin(2.0 * lng * PI)) * 2.0 / 3.0; ret += (20.0 * Math.sin(lng * PI) + 40.0 * Math.sin(lng / 3.0 * PI)) * 2.0 / 3.0; ret += (150.0 * Math.sin(lng / 12.0 * PI) + 300.0 * Math.sin(lng / 30.0 * PI)) * 2.0 / 3.0; return ret } /** * 判断是否在国内,不在国内则不做偏移 * @param lng * @param lat * @returns {boolean} */ function out_of_china(lng, lat) { return (lng < 72.004 || lng > 137.8347) || ((lat < 0.8293 || lat > 55.8271) || false); }
还有另一个算法,来自这里,经测试,算法结果是一样的。
https://github.com/hiwanz/wgs2mars.js/
----------------------- 华丽的分割线 ------------------------
C语言版本,来自
https://github.com/Dronaldo17/ChinaMapShift/blob/master/algorithm/china_shift.c
// // china_shift.c // // Most code created by someone anonymous. Thank you, someone. // transformFromGCJToWGS() added by Fengzee (fengzee@fengzee.com). // #include "china_shift.h" #include <math.h> Location LocationMake(double lng, double lat) { Location loc; loc.lng = lng, loc.lat = lat; return loc; } /// /// Transform WGS-84 to GCJ-02 (Chinese encrypted coordination system) /// const double pi = 3.14159265358979324; // // Krasovsky 1940 // // a = 6378245.0, 1/f = 298.3 // b = a * (1 - f) // ee = (a^2 - b^2) / a^2; const double a = 6378245.0; const double ee = 0.00669342162296594323; int outOfChina(double lat, double lon) { if (lon < 72.004 || lon > 137.8347) return 1; if (lat < 0.8293 || lat > 55.8271) return 1; return 0; } double transformLat(double x, double y) { double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * sqrt(x > 0 ? x:-x); ret += (20.0 * sin(6.0 * x * pi) + 20.0 *sin(2.0 * x * pi)) * 2.0 / 3.0; ret += (20.0 * sin(y * pi) + 40.0 * sin(y / 3.0 * pi)) * 2.0 / 3.0; ret += (160.0 * sin(y / 12.0 * pi) + 320 * sin(y * pi / 30.0)) * 2.0 / 3.0; return ret; } double transformLon(double x, double y) { double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(x > 0 ? x:-x); ret += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0; ret += (20.0 * sin(x * pi) + 40.0 * sin(x / 3.0 * pi)) * 2.0 / 3.0; ret += (150.0 * sin(x / 12.0 * pi) + 300.0 * sin(x / 30.0 * pi)) * 2.0 / 3.0; return ret; } Location transformFromWGSToGCJ(Location wgLoc) { Location mgLoc; if (outOfChina(wgLoc.lat, wgLoc.lng)) { mgLoc = wgLoc; return mgLoc; } double dLat = transformLat(wgLoc.lng - 105.0, wgLoc.lat - 35.0); double dLon = transformLon(wgLoc.lng - 105.0, wgLoc.lat - 35.0); double radLat = wgLoc.lat / 180.0 * pi; double magic = sin(radLat); magic = 1 - ee * magic * magic; double sqrtMagic = sqrt(magic); dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); dLon = (dLon * 180.0) / (a / sqrtMagic * cos(radLat) * pi); mgLoc.lat = wgLoc.lat + dLat; mgLoc.lng = wgLoc.lng + dLon; return mgLoc; } /// /// Transform GCJ-02 to WGS-84 /// Reverse of transformFromWGSToGC() by iteration. /// /// Created by Fengzee (fengzee@fengzee.me). /// Location transformFromGCJToWGS(Location gcLoc) { Location wgLoc = gcLoc; Location currGcLoc, dLoc; while (1) { currGcLoc = transformFromWGSToGCJ(wgLoc); dLoc.lat = gcLoc.lat - currGcLoc.lat; dLoc.lng = gcLoc.lng - currGcLoc.lng; if (fabs(dLoc.lat) < 1e-7 && fabs(dLoc.lng) < 1e-7) { // 1e-7 ~ centimeter level accuracy // Result of experiment: // Most of the time 2 iterations would be enough for an 1e-8 accuracy (milimeter level). // return wgLoc; } wgLoc.lat += dLoc.lat; wgLoc.lng += dLoc.lng; } return wgLoc; } /// /// Transform GCJ-02 to BD-09 /// const double x_pi = 3.14159265358979324 * 3000.0 / 180.0; Location bd_encrypt(Location gcLoc) { double x = gcLoc.lng, y = gcLoc.lat; double z = sqrt(x * x + y * y) + 0.00002 * sin(y * x_pi); double theta = atan2(y, x) + 0.000003 * cos(x * x_pi); return LocationMake(z * cos(theta) + 0.0065, z * sin(theta) + 0.006); } /// /// Transform BD-09 to GCJ-02 /// Location bd_decrypt(Location bdLoc) { double x = bdLoc.lng - 0.0065, y = bdLoc.lat - 0.006; double z = sqrt(x * x + y * y) - 0.00002 * sin(y * x_pi); double theta = atan2(y, x) - 0.000003 * cos(x * x_pi); return LocationMake(z * cos(theta), z * sin(theta)); }
----------------------- 华丽的分割线 ------------------------
C#算法,来自
https://on4wp7.codeplex.com/SourceControl/changeset/view/21483#353936
// // Copyright (C) 1000 - 9999 Somebody Anonymous // NO WARRANTY OR GUARANTEE // using System; namespace Navi { class EvilTransform { const double pi = 3.14159265358979324; // // Krasovsky 1940 // // a = 6378245.0, 1/f = 298.3 // b = a * (1 - f) // ee = (a^2 - b^2) / a^2; const double a = 6378245.0; const double ee = 0.00669342162296594323; // // World Geodetic System ==> Mars Geodetic System public static void transform(double wgLat, double wgLon, out double mgLat, out double mgLon) { if (outOfChina(wgLat, wgLon)) { mgLat = wgLat; mgLon = wgLon; return; } double dLat = transformLat(wgLon - 105.0, wgLat - 35.0); double dLon = transformLon(wgLon - 105.0, wgLat - 35.0); double radLat = wgLat / 180.0 * pi; double magic = Math.Sin(radLat); magic = 1 - ee * magic * magic; double sqrtMagic = Math.Sqrt(magic); dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi); mgLat = wgLat + dLat; mgLon = wgLon + dLon; } static bool outOfChina(double lat, double lon) { if (lon < 72.004 || lon > 137.8347) return true; if (lat < 0.8293 || lat > 55.8271) return true; return false; } static double transformLat(double x, double y) { double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.Sqrt(Math.Abs(x)); ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0; ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0; ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0; return ret; } static double transformLon(double x, double y) { double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.Sqrt(Math.Abs(x)); ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0; ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0; ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0 * pi)) * 2.0 / 3.0; return ret; } } }